All categories

1 year ago

Nandita earned $224 last month.

Mathematics

1 answer:

dexar [7]1 year ago

4 0

Answer:

X = 8 x 28 = 224

Nandita earns $8 last month by babysitting.

Step-by-step explanation:

225

divided by

You might be interested in

Aramis is adjusting a satellite because he finds it is not focusing the incoming radio waves perfectly. The shape of his satelli

Alika [10]

Given the equation of the parabola

$(x-4)^2=3(y-3).$

The vertex of this parabola is placed at point (4,3).

If the equation of the parabola is $(x-x_0)^2=2p(y-y_0),$ then

$2p=3,\\ \\p=1.5.$

The coordinates of the parabola focus are

$\left(x_0,y_0+\dfrac{p}{2}\right).$

Therefore, the focus is placed at point (4,3,75).

Answer: option D, 0.75 in. above the vertex

3 0

2 years ago

Read 2 more answers

It has been estimated that only about 30% of California residents have adequate earthquake supplies. Suppose we are interested i

lidiya [134]

Answer:

Step-by-step explanation:

We are given that 30% of California residents have adequate earthquake supplies.

a) Ramon variable X denotes the number of the california residents that have adequate earthquake insurance

B) x can take value 1 ,2 ,3 ......

C)The distribution of random variable is geometric distribution with parameter p=0.3

The pmf of geometric distribution is

$P(X=x)=0.3(1-0.3)^{x-1} , x=1,2,3...$

D)P(X=1) or P(X=2)=P(X=1)+P(X=2)

P(X=1) or P(X=2)= $0.3(1-0.3)^{1-1}+0.3(1-0.3)^{2-1}=0.51$

$P(X \geq 3)=1-P(X$

$E(X)=\frac{1}{p}$

p is the resident who does not have adequate earthquake supplies.

p = 1-0.3 = 0.7

$E(X)=\frac{1}{0.7}=1.42$

G) $E(X)=\frac{1}{q}=\frac{1}{0.3}=3.33$

8 0

2 years ago

Trisomy 18 (T18) is a rare genetic disorder that severely disrupts a baby's development prior to birth. Many die before birth an

Evgesh-ka [11]

Answer:

3.74% probability that her baby has T18

Step-by-step explanation:

Bayes Theorem:

Two events, A and B.

$P(B|A) = \frac{P(B)*P(A|B)}{P(A)}$

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.

In this question:

Event A: Positive test.

Event B: The baby having T18.

T18 occurs in only 1 in 2500 pregnancies in the U.S.

This means that $P(B) = \frac{1}{2500} = 0.0004$

The probability of a positive test result for a baby with T18 is 0.97.

This means that $P(A|B) = 0.97$

The overall probability of a positive test result is 0.010384.

This means that $P(A) = 0.010384$

What is the probability that her baby has T18

$P(B|A) = \frac{0.0004*0.97}{0.010384} = 0.0374$

3.74% probability that her baby has T18

5 0

2 years ago

You write 4 different names on index cards.You shuffle the cards and then lay them out in a row. What is probability that they w

MA_775_DIABLO [31]

It would be B- 1/24.

3 0

2 years ago

Now let's assume that you have a newer toilet that uses 6 L per flush, but you are considering upgrading to a dual-flush toilet.

nydimaria [60]

Answer: 3,285 Liters

Step-by-step explanation:

In the actual case, all your flushes consume 6 L of water.

You flush 4 times per day, then you consume 4 times 6 L per day, this is:

4*6L = 24 L per day.

And in one year there are 365 days, then in one year you consume:

365*24 L = 8,760 L

Now, if you upgrade the toilet, now per day you use:

one time 6 L and 3 times 3 L

Then in day, you use:

1*6 L + 3*3 L = 6L + 9L = 15L

And in the complete year, you will use 365 times that, which is:

365*15 L = 5,475 L

The amount of water that you would save is equal to the difference between the amount that you use in one year with no upgrade (8,760 L) and the amount that you would use in a year if you upgraded your toilet ( 5,475 L)

The difference is:

D = 8,760 L - 5,475 L = 3,285 L

This means that, in this situation, you would save 3,285 liters of water per year if you upgrade your toilet.

8 0

1 year ago