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2 years ago

Nandita earned $224 last month.

Mathematics

1 answer:

dexar [7]2 years ago

4 0

Answer:

X = 8 x 28 = 224

Nandita earns $8 last month by babysitting.

Step-by-step explanation:

225

divided by

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There are four activities on the critical path, and they have standard deviations of 1, 2, 4, and 2. what is the probability tha

Anit [1.1K]

Standard deviations of the four activities of the critical path are 1,2,4,2.

Standard deviation of this critical path = Sum of square root of variance of this corresponding critical path

Standard deviation of critical path $=\sqrt{1^2+2^2+4^2+2^2}$

$=\sqrt{1+4+16+4}$

$=\sqrt{25}$

$=5$

Now we need to find the probability that the project will completed in 38 weeks given that its expected completion time is 40 weeks.

That is, we need to find P(X<38) :

$z=\frac{38-40}{5}= \frac{-2}{5}=-0.4$

$P(X$

Probability $=0.5-0.16=0.34$

Thus the probability that the project will be completed in 38 weeks is 0.34.

8 0

2 years ago

Read 2 more answers

Consider the set of differences, denoted with d, between two dependent sets: 84, 85, 83, 63, 61, 100, 98. Find the sample standa

sveta [45]

Answer:

The sample standard deviation is 15.3.

Step-by-step explanation:

Given data items,

84, 85, 83, 63, 61, 100, 98,

Number of data items, N = 7,

Let x represents the data item,

Mean of the data points,

$\bar{x}=\frac{84+85+83+63+61+100+98}{7}$

$=82$

Hence, sample standard deviation would be,

$\sigma= \sqrt{\frac{1}{N-1}\sum_{i=1}^{N} (x_i-\bar{x})^2}$

$=\sqrt{\frac{1}{6}\sum_{i=1}^{7} (x_i-82)^2}$

$=\sqrt{\frac{1}{6}\times 1396}$

$=\sqrt{232.666666667}$

$=15.2534149182$

$\approx 15.3$

4 0

2 years ago

If e = 9 cm and f = 40 cm, what is the length of g?

rewona [7]

(9,40,41) is a Pythagorean Triple, farther down the list than teachers usually venture.

Answer: D. 41 cm

There's a subset of Pythagorean Triples where the long leg is one less than the hypotenuse,

a^2+b^2 = (b+1)^2

a^2 + b^2 = b^2 + 2b +1

a^2=2b+1

So we get one for every odd number, since the square of an odd number is odd and the square of an even number is even.

b = (a^2 - 1)/2

a=3, b=(3^2-1)/2=4, c=b+1=5

a=5, b=(5^2-1)/2 =12, c = 13

a=7, b=24, c=25

a=9, b=40, c=41

a=11, b=60, c=61

a=13, b=84, c=85

It's good to be able to recognize Pythagorean Triples when we see them.

Otherwise we'd have to work the calculator:

√(9² + 40²) = √1681 = 41

8 0

2 years ago

What is the y-intercept of the polynomial f(x)f(x) f(x) defined below? Write the y-value only. f(x)=−4x2+x5+10x3+5x+8x4f(x)=-4x^

zhannawk [14.2K]

Answer:

y = 0

Step-by-step explanation:

Given

f(x) = 4x² +x⁵ +10x³ +5x+8x⁴

Required

Determine the y intercept

The y intercept of a function is a point where x = 0

So, we have to substitute 0 for x in the above function

f(x) = 4x² +x⁵ +10x³ +5x+8x⁴ becomes

f(0) = 4(0)² +(0)⁵ +10(0)³ +5(0)+8(0)⁴

f(0) = 4 * 0 + 0 + 10 * 0 + 5 * 0 + 8 * 0

f(0) = 0 + 0 + 0 + 0 + 0

f(0) = 0

Substitute y for f(0)

y = 0

Hence, the y intercept is 0

4 0

2 years ago

Food allergies affect an estimated 7% of children under age 5 in the US. What is the probability that in a kindergarden class of

bezimeni [28]

Answer:

Probability of atleast one of 12 student has food allergies ≈ 0.58 ( approx)

Step-by-step explanation:

Given: Probability of a children under age 5 has food allergies = 7%

= $\frac{7}{100}$

To find : Probability of atleast one of 12 student has food allergies

Probability of a chindren under age 5 does not have food allergies = $1-\frac{7}{100}$

⇒ prob = $\frac{93}{100}$

now we find Probability of atleast one of 12 student has food allergies this means we have to find prob of 1 student, 2 student, 3 student, till 12 student have allergy out of 12 student of class then add all prob.

But instead of finding all these probability we find probability of student having no allergy.i.e., 0 student then subtract it from 1(total probability)

Probability of 0 student having allergy out of 12 student = $(\frac{93}{100})^{12}$

Therefore, Probability of atleast one of 12 student has food allergies

= $1-(\frac{93}{100})^{12}$

= $0.581403702521$

≈ 0.58 ( approx)

8 0

2 years ago

Read 2 more answers