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vlada-n [284]
2 years ago
13

A cell phone charger uses 4.83 joules per second when plugged into an outlet, but only 1.31 joules per

Physics
1 answer:
Tamiku [17]2 years ago
5 0
Well, that depends on how you look at it.

Efficiency =

       <em>(amount of power that does what you want) / (total power supplied)</em>.

Power to charge battery . . . 1.31 watts
Power changed to heat . . .  3.52 watts
Total power supplied . . . . . . 4.83 watts

Using the cell-phone as a heater,
efficiency of the charger in supplying heat = 3.52 / 4.83 =  <em>72.9 %</em> .

Using the cell-phone as cell-phone,
efficiency of the charger in charging the battery = 1.31 / 4.83 =  <em>27.1 %</em> .

The charger is more efficient as a heater than it is as a battery charger.

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A target in a shooting gallery consists of a vertical square wooden board, 0.250 m on a side and with mass 0.750 kg, that pivots
Alenkasestr [34]

Here in this case since there is no torque about the hinge axis for the system of bullet and block then we can say that angular momentum of this system will remain conserved

L_i = L_f

mv \frac{L}{2} = (I_1 + I_2)\omega

here we will have

L = 0.250 m

v = 385 m/s

m = 1.90 gram

now moment of inertia of the plate will be

I_1 = \frac{ML^2}{3}

I_1 = \frac{0.750 (0.250)^2}{3} = 0.0156 kg m^2

I_2 = m(\frac{L}{2})^2 = 0.0019(0.125)^2 = 2.97 \times 10^{-5} kg m^2

now from above equation

0.0019 (385)(0.125) = (0.0156 + 2.97 \times 10^{-5})\omega

\omega = 5.85 rad/s

8 0
2 years ago
A runner generates 1260 W of thermal energy. If this heat has to be removed only by evaporation, how much water does this runner
sergey [27]

Answer:0.502kg

Explanation:

F4om the relation

Power x time = mass x latent heat of vapourization

P.t=ML

1260 * 15 *60 = M * 22.6 * 10^5

M= 1134000/(22.6 *10^5)

M=0.502kg=502g

3 0
2 years ago
A 3kW oven supplied with 9mJ of energy.How many minutes can it run for?
andreev551 [17]

<span>Hello!
 
We have the following data:
</span>
Time (T) = ? (in minutes)
Power (P) = 3 kW → 3000 W
Energy (E) = 9 MJ → 9000000 J or (W/s)

Formula of the consumption of electric energy:

P =  \frac{E}{T}

Solving:

P = \frac{E}{T}

P = \frac{E}{T} \to T =  \frac{E}{P}

T =  \frac{9000\diagup\!\!\!\!0\diagup\!\!\!\!0\diagup\!\!\!\!0\:\diagup\!\!\!\!W/s}{3\diagup\!\!\!\!0\diagup\!\!\!\!0\diagup\!\!\!\!0\:\diagup\!\!\!\!W}

\boxed{T = 3000\:seconds}

How many minutes can it run for? (<span>Let's convert in minutes)
</span>
1 minute --------- 60 seconds
y minute --------- 3000 seconds

\frac{1}{y} = \frac{60}{3000}

<span>Product of extremes equals product of means
</span>
60*y = 1*3000

60y = 3000

y =  \frac{3000}{60}

\boxed{\boxed{y = 50\:minutes}}\end{array}}\qquad\quad\checkmark


I hope this helps! =)
<span>

</span>
7 0
2 years ago
Read 2 more answers
Robin Hood wishes to split an arrow already in the bull's-eye of a target 40 m away.
tamaranim1 [39]

Answer:

5.843 m

Explanation:

suppose that the arrow leave the bow with a horizontal speed , towards he bull's eye.

lets consider that horizontal motion

distance = speed * time

time = 40/ 37 = 1.081 s

arrow doesnot have a initial vertical velocity component. but it has a vertical motion due to gravity , which may cause a miss of the target.

applying motion equation

(assume g = 10 m/s²)

s=ut+\frac{1}{2}*gt^{2}  \\= 0+\frac{1}{2}*10*1.081^{2}\\= 5.843 m

Arrow misses the target by 5.843m ig the arrow us split horizontally

4 0
2 years ago
Volcanoes are often formed at plate boundaries. This is a convergent plate boundary. From the choices listed, pick the correct d
katen-ka-za [31]
Your answer should be a
8 0
2 years ago
Read 2 more answers
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