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2 years ago

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An inductor has an inductance of 0.025 H and a wire resistance of . How long will it take the current to reach its full Ohm’s la

w value?

1 answer:

Talja [164]2 years ago

3 0

Answer:

Time constant t = 0.0083 (Approx)

Explanation:

Given:

L = 0.025

Missing resistance r = 3Ω

Find:

Time constant t

Computation:

Time constant t = L / r

Time constant t = 0.025 / 3

Time constant t = 0.0083 (Approx)

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Write a method printShampooInstructions(), with int parameter numCycles, and void return type. If numCycles is less than 1, prin

kirill [66]

Answer:

// The method is defined with a void return type

// It takes a parameter of integer called numCycles

// It is declared static so that it can be called from a static method

public static void printShampooInstructions(int numCycles){

// if numCycles is less than 1, it display "Too few"

if (numCycles < 1){

System.out.println("Too few.");

}

// else if numCycles is less than 1, it display "Too many"

else if (numCycles > 4){

System.out.println("Too many.");

}

// else it uses for loop to print the number of times to display

// Lather and rinse

else {

for(int i = 1; i <= numCycles; i++){

System.out.println(i + ": Lather and rinse.");

}

System.out.println("Done");

}

}

Explanation:

The code snippet is written in Java. The method is declared static so that it can be called from another static method. It has a return type of void. It takes an integer as parameter.

It display "Too few" if the passed integer is less than 1. Or it display "Too much" if the passed integer is more than 4. Else it uses for loop to display "Lather and rinse" based on the passed integer.

8 0

2 years ago

The top 3 most popular male names of 2017 are Oliver, Declan, and Henry according to babynames. Write a program that modifies th

Flura [38]

Answer:

The code is given below in Python with appropriate comments

Explanation:

# convert list to set

male_names = set(['Oliver','Declan','Henry'])

# get remove and add name from user

remove_name = input("Enter remove name: ")

add_name = input("Enter add name: ")

# remove name from set

male_names.remove(remove_name)

# add new name ij set

male_names.add(add_name)

# sort the set

a = sorted(male_names)

# print the set

print(a)

7 0

2 years ago

estimate the area for a landfill for 12000 p producing waste for 10 y. assume that the national average is

ELEN [110]

Answer:

1.015 ha.

Explanation:

In order to be able to calculate the area for the landfill for 12000 p producing waste for 10 y the following steps must be taken.

STEP ONE: Determine the average solid waste production in kg p^-1 ^y(kg/py).

From the question, we have that average solid waste production is 2.78 kg p^-1 d^- (kg/pd) hence, to change it to kg/py we have;

2.78 × 365 days = 1014.7 kg/py.

STEP TWO: determine the volume of refuse per person in a year.

Thus the volume = 1014.7 kg/py ÷ 500 kg/m^3 = 2.03 m^3 p^- y^-.

STEP THREE: Determine the total volume of solid waste in 10y by 12,000.

Toy volume in 10y = 10 × 12,000 × 2.03 = 243,600 m^3.

STEP FOUR: Determine the are of the landfill.

NB: the total height for the landfill should be 20 + 4 = 24m.

Therefore, the area of the landfill= 243,600 m^3. / 24m = 10,150m^2.

If 10000 m^2 = 1 ha. Then, 10,150m^2 ÷ 10000 m^2 = 1.015 ha.

(f). Make sure to increase the landfill area for improvement.

4 0

2 years ago

Which of these is true about airbag charts?

Arlecino [84]

A should be it or b

4 0

2 years ago

A heat pump is to be used to heat a house in winter and then reversed to cool the house in summer. The interior space is to be m

DochEvi [55]

Answer:

$35.07\°C$

Explanation:

To solve this exercise, it is necessary to apply the concepts of Performance Coefficient and work.

For part A, we have given the data on the outside temperature, which is 5°C. In this way the rate of heat loss in the room is given by

$\dot{Q} = \xi \Delta T$

where,

$\xi =$ Heat transfer per second

$\Delta T =$ Change in Temperature

We have then,

$\dot{Q} = 0.525(20-5)$

$\dot{Q} = 7.8749kW$

Now we can calculate the coefficient of performance which is given by,

$COP = \frac{T}{\Delta T}$

$COP = \frac{20}{20-5}$

$COP = 19.53$

By definition we know that the coefficient of performance of a pump is given by

$COP = \frac{\dot{Q}}{W}$

where,

$\dot{Q} =$ Desired effect

W = Work input

Solving for the work input we have

$W = \frac{\dot{Q}}{COP}$

$W = \frac{7.875}{19.33}$

$W = 0.407kW$

For part B we consider $\tau$ as the maximum temperature outside, therefore, calculating the heat rate we have

$\dot{Q}=0.525*(T-293)Kj/S$

$\dot{Q} = 525*(T-293)W$

Returning to the expression of the coefficient of performance we have to,

$COP = \frac{\dot{Q}}{W}$

$0.407kW = \frac{525*(T-293)}{\frac{293}{T-293}}$

$(T-293)^2 = \frac{403*293}{525}$

$T^2-586T+85849=225$

$T^2-586T+85624=0$

Solving the polynomial you have to

$T= 308K = 35\°C$

Therefore the maxium outside temperature is $35\°C$

3 0

2 years ago

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