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spin [16.1K]
1 year ago
15

The function shown is reflected across the y-axis to create a new function. Which is true about the domain and range of each fun

ction? Both the domain and range change. Both the range and domain stay the same. The domain stays the same, but the range changes. The range stays the same, but the domain changes.
Mathematics
2 answers:
Alenkinab [10]1 year ago
8 0

Answer:

D. The range stays the same but the domain changes

Step-by-step explanation:

mark brainliest

marin [14]1 year ago
8 0

Answer:

its b friends :)

Step-by-step explanation:

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How are the two functions f(x) = 0.7(6)x and g(x) = 0.7(6)–x related to each other?
Harlamova29_29 [7]
The answer
f(x) = 0.7(6)x = <span>f(x) = 0.7(6)^x, and  </span><span>g(x) = 0.7(6)–x= </span>g(x) = 0.7(6)^-x=1/<span>0.7(6)^x
so </span>
g(x) =1/<span>0.7(6)^x=1 /</span><span><span>f(x)

</span> the relationship between f and g are </span>g(x) =1 /<span>f(x) or </span><span>g(x) . <span>f(x) = 1</span> </span>






7 0
2 years ago
Read 2 more answers
A rectangle that has an area of 357 square inches is 17 inches wide. Using the formula for area (4072-01-01-03-00_files/i0260000
Masja [62]
A = L * W
A = 357
W = 17

357 = 17L
357 / 17 = L
21 = L <== length is 21 inches

8 0
1 year ago
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you plan to buy a bicycle that will cost at least 180. you have saved 38 and your parents have given you 50. how much more money
shutvik [7]

Answer:

$92

Step-by-step explanation:

  • add what you saved and the parents gave you
  • subtract that by 180
  • $92
4 0
1 year ago
What is the area of △FGH to the nearest tenth of a square meter? The image is of a triangle GHF with base GH length 2m, FG is 2.
Gnesinka [82]
First, we are going to use the law of cosines to find the length of the line segment FH:
FH= \sqrt{2.5^{2}+2^{2}-(2)(2.5)Cos(121)}
FH= \sqrt{2.5^{2}+2^{2}-5Cos(121)}
FH=3.2

Next, we are going to use the semi-perimeter formula: s= \frac{GH+FG+FH}{2}
s= \frac{2+2.5+3.2}{2}
s= \frac{7.7}{2}
s=3.9

Now that we have the semi-perimeter of our triangle, we can find its area using Heron's formula:
A= \sqrt{s(s-GH)(s-FG)(s-FH)}
A= \sqrt{3.9(3.9-2)(3.9-2.5)(3.9-3.2)}
A= \sqrt{3.9(1.9)(1.4)(0.7)}
A=2.7m^{2}

We can conclude that the area of the triangle <span>GHF is 2.7 </span>m^{2}.

3 0
2 years ago
You stand outside of a swimming pool at point C. Calculate the radius of the swimming pool.
Elenna [48]

Answer:

bruh whats the answer?

Step-by-step explanation:

8 0
1 year ago
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