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spin [16.1K]
2 years ago
15

The function shown is reflected across the y-axis to create a new function. Which is true about the domain and range of each fun

ction? Both the domain and range change. Both the range and domain stay the same. The domain stays the same, but the range changes. The range stays the same, but the domain changes.
Mathematics
2 answers:
Alenkinab [10]2 years ago
8 0

Answer:

D. The range stays the same but the domain changes

Step-by-step explanation:

mark brainliest

marin [14]2 years ago
8 0

Answer:

its b friends :)

Step-by-step explanation:

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Complete the sentence. the roots of the equation x^2 - 8x - 48 = 0 are -4 and *blank*
prisoha [69]

Answer:

12 is the answer.

Step-by-step explanation:

The best way to get the roots of the equation is to factorize the equation but when the factors are not possible then we should apply the quadratic equations formula to get the value of x.

Now we will try to factorize

x² - 8x -48 = 0

Now we multiply coefficient of highest degree term and constant term

48×1 = 48 which may be factored in 12×4. 8×6, 24×2.

Now we will choose 12×4 out of three because the 12-4 = 8 which is the coefficient of x.

Now its simple.

x²-12x + 4x -48 = 0

x(x -12) + 4(x-12) = 0

(x +4)(x-12) = 0

Therefore roots are x + 4 = 0

x = -4

and x - 12 = 0

x = 12

So the answer is 12.

8 0
2 years ago
Read 2 more answers
Find a single expression that represents the area of the outer ring of the circle if the area of the whole circle is represented
sp2606 [1]

Answer:  The answer is A_o=2\pi\sqrt{\dfrac{7}{22}(25x^2-12x-9)}.


Step-by-step explanation: Given that the area of the whole circle is represented by the expression

A_c=25x^2-12x-9.

We are to find the area of the outer ring of the circle, i.e., to find the circumference of the circle.

Now, if 'r' represents the radius of the circle, then we have

A_c=\pi r^2\\\\\Rightarrow \dfrac{22}{7}r^2=25x^2-12x-9\\\\ \Rightarrow r^2=\dfrac{7}{22}(25x^2-12x-9)\\\\\Rightarrow r=\sqrt{\dfrac{7}{22}(25x^2-12x-9)}.

Thus, the area of the outer ring is

A_o=2\pi r=2\pi\sqrt{\dfrac{7}{22}(25x^2-12x-9)}.


5 0
2 years ago
Mia has a conical container filled with chocolates. She knows that the volume of the container is equal to one-third of the prod
34kurt
For this case what you should do is create the equation based on:
 "She knows that the volume of the container is equal to one-third of the product, the square of the radius of the base of the container, and the height of the container"
 We have then that the Volume is given by:
 V = (1/3) * (r ^ 2) * (h)
 where,
 r: radius of the base.
 h: height of the container.
 answer
 The volume of the container is calculated with the following equation:
 V = (1/3) * (r ^ 2) * (h)
7 0
2 years ago
Read 2 more answers
Ivan found the change in a scale factor. His work is shown below. What error did Ivan make?
Tresset [83]
Scale factor is:
factor = (new length) / (old length)
Ivan correctly inserted numbers and correctly divided these two numbers by 5.

There is no error in the shown picture.
5 0
2 years ago
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The perimeter of a rectangle is represented by 4x2 + 5x − 2. The perimeter of a smaller rectangle is represented by x2 + 3x + 5.
REY [17]
<span>4x2 +5x - 2 -x2 +3x +5 Simplified: 3x2 + 8x +3 In order to determine the difference in size, you must subtract the perimeter of the smaller rectangle from the perimeter of the larger rectangle.</span>
6 0
2 years ago
Read 2 more answers
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