PLEASE HELP ASAP (I NEED HELP) !

$53,000 is placed in an investment account that grows at a fixed rate of 2% (compound growth) per year. how much is in the accou

ella [17]

Answer:

$57,369

Step-by-step explanation:

We have been given that an amount of $53,000 is placed in an investment account that grows at a fixed rate of 2% (compound growth) per year. We are asked to find the amount in the account after 4 years.

To solve our given problem we will use compound interest formula.\

$A=P(1+\frac{r}{n})^{nt}$ , where,

A = Final amount after t years,

P = Principal amount,

r = Annual interest rate in decimal form,

n = Number of times interest is compounded per year,

t = Time in years.

Let us convert our given rate in decimal form.

$2\%=\frac{2}{100}=0.02$

Upon substituting our given values in compound interest formula we will get,

$A=\$53,000(1+\frac{0.02}{1})^{1*4}$

$A=\$53,000(1+0.02)^{4}$

$A=\$53,000(1.02)^{4}$

$A=\$53,000*1.08243216$

$A=\$57368.90448\approx \$57,369$

Therefore, an amount of $57,369 will be in the account after 4 years.

3 0

2 years ago

A 6-meter pole is supported by guy wires that are anchored to the ground as shown. What is sin D?

kap26 [50]

Answer:

0.8941

Step-by-step explanation:

sin D = opp / hyp = 6 m / 6.71 m = 0.8941

8 0

2 years ago

Read 2 more answers

The growth in the mouse population at a certain county dump can be modeled by the exponential function A(t)= 906e0.012t, where t

tatyana61 [14]

Answer:

$A(t) = 906 e^{0.012t}$

Where t is the number of months since the population was first recorded. And we want to find the population after 36 months so we need to replace t=36 months into the function and we got:

$A(36) = 906 e^{0.012*36}= 1395.54$

So then we can conclude that after 36 months the population of mouse is between 1385 and 1396.

Step-by-step explanation:

We know that the population can be represented with this formula:

$A(t) = 906 e^{0.012t}$

Where t is the number of months since the population was first recorded. And we want to find the population after 36 months so we need to replace t=36 monthsinto the function and we got:

$A(36) = 906 e^{0.012*36}= 1395.54$

So then we can conclude that after 36 months the population of mouse is between 1385 and 1396.

5 0

2 years ago

(2.5 points) The probability that an airplane accident which is due to structural failure is diagnosed correctly is 0.85 and the

Nikitich [7]

Answer: 0.51

Step-by-step explanation:

This is a conditional probability. The first event is the airplane accident being caused by structural failure. The probability of it being due to structural failure is 0.3 and the probability of it not being due to structural failure is 0.7. The second event involves the diagnosis of the event. If a plane fails due to structural failure, the probability that it will be diagnosed and the results will say it was due to structural failure is 0.85, and the probability that the diagnosis is unable to identify that it was because of a structural failure is 0.15. If the plane were to fail as a result of some other reason aside structural failure, the probability that the diagnosis will show that it was as a result of structural failure is 0.35 and the probability of the diagnosis showing that is is not as a result of structural failure is 0.65. To find the probability that an airplane failed due to structural failure given that it was diagnosed that it failed due to some malfunction, this is the equation;

p = (probability of plane failing and diagnosis reporting that the failure was due to structural failure)/ (probability of diagnosis reporting that failure was due to structural failure)

p = (0.3*0.85)/((0.3*0.85) + (0.7*0.35))

p = 0.51

4 0

2 years ago

The probability that Jane will go to a ballgame (event A) on a Monday is 0.73, and the probability that Kate will go to a ballga

cricket20 [7]

Events A and B are called independent, when

$Pr(A\cap B)=Pr(A)\cdot Pr(B),$