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Irina-Kira [14]
1 year ago
7

Before any dinner service, the manager confirms when the number of reservations at a restaurant is subtracted from twice the num

ber of loaves of bread on hand must be greater than 5. Which graph represents the overall equation represented by this scenario (all points may not apply to the scenario)? On a coordinate plane, a dashed straight line has a positive slope and goes through (0, negative 5) and (3, 1). Everything to the right of the line is shaded. On a coordinate plane, a dashed straight line has a positive slope and goes through (0, negative 5) and (3, 1). Everything to the left of the line is shaded. On a coordinate plane, a dashed straight line has a negative slope and goes through (negative 3, 1) and (0, negative 5). Everything to the left of the line is shaded. On a coordinate plane, a dashed straight line has a negative slope and goes through (negative 3, 1) and (0, negative 5). Everything to the right of the line is shaded.
Mathematics
1 answer:
AlexFokin [52]1 year ago
3 0

Answer:

A

Step-by-step explanation:

You might be interested in
Keenan currently does a total of 888 pushups each day. He plans to increase the number of pushups he does each day by 222 pushup
marishachu [46]

Answer:

8 + 2x = 30

Step-by-step explanation:

Given,

The initial number of push-ups he does in each day = 8,

And, the number of push-ups, he increases per day = 2,

Let x be the number of days after he will reach his target of 30 push-ups,

Since, the number of push-ups she will increase in x days = 2x,

Thus, the number of push-ups she will do after x days = 8 + 2x,

⇒ 8 + 2x = 30, which is the required equation.

4 0
1 year ago
Maggie bought 3/4 of a pound of bananas and 4 boxes of cereal for $10.11. If each box of cereal cost $2.40, what was the price o
beks73 [17]
If you had 4 boxes of cereal and each costs $2.40, the total cost would be $9.60 (2.40×4).

The total cost of the bananas and the cereal cost $10.11. To find how much the 3/4 of bananas cost, simply subtract $9.60 away from $10.11 (10.11-9.6), which gives you $0.51.

The question asks for 1 pound of bananas but you only have the cost of 3/4. So, divide your cost by 3 to give you the cost of 1/4. (0.51÷3), which gives you $0.17.

The last step is to multiply this answer by 4 because 4/4 will result in a whole, or in this case, one pound (0.17×4) and thus gives you the cost $0.68 for one pound of bananas.

(please correct me if I'm wrong, hope this helped c: )
6 0
1 year ago
Read 2 more answers
Ramon is interested in whether the global rise in temperature is also showing up locally in his town, Centerdale. He plans to lo
denis-greek [22]

Answer:

d. The random variable is the number of years in which the temperature increased from the previous year.

Step-by-step explanation:

The random variable is the amount of years that have higher average temperatures than its previous year.

As the sample is from 5 years, the random variable can take values from 0 (where none of the years increase their average temperature from its previous year) to 4 (where every year increases the average temperature).

8 0
2 years ago
Let P and Q be polynomials with positive coefficients. Consider the limit below. lim x→[infinity] P(x) Q(x) (a) Find the limit i
jenyasd209 [6]

Answer:

If the limit that you want to find is \lim_{x\to \infty}\dfrac{P(x)}{Q(x)} then you can use the following proof.

Step-by-step explanation:

Let P(x)=a_{n}x^{n}+a_{n-1}x^{n-1}+\cdots+a_{1}x+a_{0} and Q(x)=b_{m}x^{m}+b_{m-1}x^{n-1}+\cdots+b_{1}x+b_{0} be the given polinomials. Then

\dfrac{P(x)}{Q(x)}=\dfrac{x^{n}(a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)}+a_{0}x^{-n})}{x^{m}(b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m})}=x^{n-m}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)})+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}

Observe that

\lim_{x\to \infty}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)})+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}=\dfrac{a_{n}}{b_{m}}

and

\lim_{x\to \infty} x^{n-m}=\begin{cases}0& \text{if}\,\, nm\end{cases}

Then

\lim_{x\to \infty}=\lim_{x\to \infty}x^{n-m}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)}+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}=\begin{cases}0 & \text{if}\,\, nm \end{cases}

3 0
1 year ago
Which of the following accurately lists all of the discontinuities for the graph below?
Murljashka [212]

Answer:

jump discontinuity at x = 0; point discontinuities at x = –2 and x = 8

Step-by-step explanation:

From the graph we can see that there is a whole in the graph at x=-2.

This is referred to as a point discontinuity.

Similarly, there is point discontinuity at x=8.

We can see that both one sided limits at these points are equal but the function is not defined at these points.

At x=0, there is a jump discontinuity. Both one-sided limits exist but are not equal.

3 0
1 year ago
Read 2 more answers
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