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Alisiya [41]
2 years ago
13

*****SOMEONE PLS HELP***** Bernite is selling candy bars for a school fundraiser. The school paid $20.00 for a box of 15 king-si

ze candy bars and Bernite sells them for $2.00 each. What is the relationship between the amount of candy sold and the amount of money earned?

Mathematics
1 answer:
Artyom0805 [142]2 years ago
3 0
I’d say it was non proportional or a negative profit but i’m not sure
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Factor 147a^2b-675b^3
Tju [1.3M]

Answer:Factor the polynomial

3(a−4b)2

8 0
2 years ago
Harry had $32. He spent all the money on buying 3 notebooks for $x each and 4 packs of index cards for $y each. If Harry had bou
LenKa [72]
3x + 4y = 32....multiply by 5
5x + 5y = 50...multiply by -3
---------------
15x + 20y = 160 (result of multiplying by 5)
-15x - 15y = -150 (result of multiplying by -3)
--------------add
5y = 10
y = 10/5
y = 2

3x + 4y = 32
3x + 4(2) = 32
3x + 8 = 32
3x = 32 - 8
3x = 24
x = 24/3
x = 8

solution (8,2)

The students conclusion is incorrect......it is answer choice 1



4 0
2 years ago
Galactic Rotation Speed. We are located about 27,000 light-years from the galactic center and we orbit the center about once eve
Alexxandr [17]

Answer:

speed = 796142.197 km/hr

Step-by-step explanation:

solution

we consider here orbit around galactic center is circular so

circumference formula will be here

circumference C = 2πr   ........1

here we know r = 27000

so

circumference C = 2 π × 27000

C = 169560 light year

so

we travel 169560 light year in 230000000 years

so distance will be

distance = \frac{169560}{230000000}

distance = 0.00073721 light year/year

and we know 1 year = 8760 hours

so 1 light year = 9.46027 ×10^{12} km

so

sped of moving is

speed = 0.00073721 × 9.46027 × \frac{10^{12}}{8760}  km/hr

speed = 796142.197 km/hr

5 0
2 years ago
Suppose that five ones and four zeros are arranged around a circle. Between any two equal bits you insert a 0 and between any tw
PolarNik [594]

Answer:

Using <u>backward reasoning</u> we want to show that <em>"We can never get nine 0's"</em>.

Step-by-step explanation:

Basically in order to create nine 0's, the previous step had to have all 0's or all 1's. There is no other way possible, because between any two equal bits you insert a 0.

If we consider two cases for the second-to-last step:

<u>There were 9 </u><u>0's</u><u>:</u>

We obtain nine 0's if all bits in the previous step were the same, thus all bit were 0's or all bits were 1's. If the previous step contained all 0's, then we have the same case as the current iteration step. Since initially the circle did not contain only 0's, the circle had to contain something else than only 0's at some point and thus there exists a point where the circle contained only 1's.

<u>There were 9 </u><u>1's</u><u>:</u>

A circle contains only 1's, if every pair of the consecutive nine digits is different. However this is impossible, because there are five 1's and four 0's (we have an odd number of bits!), thus if the 1's and 0's alternate, then we obtain that 1's that will be next to each other (which would result in a 1 in the next step). Thus, we obtained a contradiction and thus assumption that the circle contains nine 0's after iteratins the procedure is false. This then means that you can never get nine 0's.

To summarize, in order to create nine 0's, the previous step had to have all 0's or al 1's. As we didn't start the arrange with all 0's, the only way is having all 1's, but having all 1's will not be possible in our case since we have an odd number of bits.

<u />

5 0
2 years ago
Joe drew a diagram of a window as shown below. The window is formed by a square and a semicircle. The area of the square portion
abruzzese [7]

One side of the square measures 28 inches. Use 3.14 for π.

6 0
2 years ago
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