The diagram below represents the measurements of Jennie’s yard. The yard’s width is x feet shorter than its length. If the area
of the yard is 540 square feet, how many feet shorter than the length is the width?
A yard with a length of 30 feet and a width of (30 minus x) feet.
Which equation represents the scenario?
30 + (30 – x) = 540
540 – 30 = 30 – x
30(30 – x) = 540
540 – (30 – x) = 30
A yard with a length of 30 feet and a width of (30 minus x) feet.
Which equation represents the scenario?
30 + (30 – x) = 540
540 – 30 = 30 – x
30(30 – x) = 540
540 – (30 – x) = 30
2 answers:
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Answer:
For school A: Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17, IQR=9.5
For school B: Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19, IQR=7.5
No, the box plots are not symmetric.
Step-by-step explanation:
Part A
The given data sets are
School A : 9,14,15,17,17,7,15,6,6
School B : 12,8,13,11,19,15,16,5,8
Arrange the data in ascending order.
School A : 6,6,7,9,14,15,15,17,17
School B : 5,8,8,11,12,13,15,16,19
Divide each data set in four equal parts.
School A : (6,6),(7,9),14,(15,15),(17,17)
School B : (5,8),(8,11),12,(13,15),(16,19)
For school A:
Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17
Interquartile range of the data is
For school B:
Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19
Interquartile range of the data is
Part B:
The box plots are not symmetric because the data values are different. Five number summary and IQR of both the data set are different.
Answer:
C. A horizontal stretch to produce a period of and a vertical compression.
Step-by-step explanation:
We are given the parent function as
It is given that, transformations are applied to the parent function in order to obtain the function i.e.
That is, we see that,
The parent function is stretched horizontally by the factor of
which gives the function
.
Further, the function is compressed vertically by the factor of which gives the function
.
Now, we know,
If a function f(x) has period P, then the function cf(bx) will have period .
Since, the period of is
, so the period of
is
=
Hence, we get option C is correct.