Answer:
<em>a) tan x = 1</em>
<em>b) tany = 4 + tanx /2tanx - 3</em>
Step-by-step explanation:
a) Given the equation
2(sinx + 2cosx) = sinx +5cosx
Open the bracket
2sinx + 4cosx = sinx +5cosx
Collect like terms
2sinx - sinx = 5cosx - 4cosx
sinx = cos x
Divide both sides by cos x
sinx/cosx = cosx/cosx
tanx = 1
Hence the value of tan x is 1
b) Given the expression
sinxcosy + 3cosxsiny = 2sinxsiny - 4cosxcosy
We are to express tany in terms of tan x
Divide through by cosx cosy
sinxcosy/cosx cosy + 3cosxsiny/cosx cosy = 2sinxsiny/cosx cosy - 4cosxcosy/cosx cosy
sinx/cosx + 3siny/cosy = 2tanxtany - 4
tanx +3tany = 2tanxtany - 4
Collect like terms
tanx - 2tanxtany = -4 - 3tany
- 2tanxtany+3tany = -4 - tanx
tany (-2tanx+3) = -4 - tanx
tan y = -4 - tanx/-2tanx+3
tan y = -(4+tanx)/-(2tanx-3)
tany = 4 + tanx /2tanx - 3
<em>Hence the function of tany in term of tan x is tany = 4 + tanx /2tanx - 3</em>
