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alexandr402 [8]
2 years ago
15

Consumers Energy states that the average electric bill across the state is $67.16. You want to test the claim that the average b

ill amount is greater than $67.16. The hypotheses for this situation are Null Hypothesis: μ ≤ 67.16, Alternative Hypothesis: μ > 67.16. If the true statewide average bill is $51.28 and the null hypothesis is not rejected, did a type I, type II, or no error occur?
a. Type I Error has occured.
b. No error has occured.
c. We do not know the degrees of freedom, so we cannot determine if an error has occured.
d. Type II Error has occured
e. We do not know the p-value, so we cannot determine if an error has occured.
Mathematics
1 answer:
aleksandr82 [10.1K]2 years ago
5 0

Answer:

B: No error has occured

Step-by-step explanation:

In statistical hypothesis testing, we have two types of errors namely Type I error and Type II error.

Type I error occurs when we reject the null hypothesis although it is true. Meanwhile, Type II error occurs when we fail to reject the null hypothesis null hypothesis even though it is false.

Now, we are given the null and alternative hypothesis as;

Null Hypothesis: μ ≤ 67.16

Alternative Hypothesis: μ > 67.16.

Where μ represents the statewide average bill.

We are also given the true statewide average bill is $51.28.

Now, the true statewide average bill falls within the range of the null hypothesis given.

Thus, we can't reject the null hypothesis since it is true.

Now, we are told the null hypothesis is not rejected and that is correct.

Thus, there is no error as it doesn't fall into the type I or the type II error.

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A customer's stock value seems to be rising exponentially. The equation for
Rasek [7]
<h2>Hello!</h2>

The answer is:

The correct option is A. 8.3.

<h2>Why?</h2>

To calculate the number of weeks that will pass, we need to use the given information.From the statement we know that we need to use the value of $600 substituting it as "y", and then, isolate "x", so, calculating we have:

log(y)=0.30x+0.296\\\\log(600)=0.30x+0.296\\\\2.78=0.30x+0.296\\\\2.78-0.296=0.30x\\\\x=\frac{2.78-0.296}{0.30}=8.28=8.3

Hence, the correct option is A. 8.3.

Have a nice day!

4 0
2 years ago
Determine the margin of error, m , of a 99% confidence interval for the mean IQ score of all students with the disorder. Assume
madreJ [45]

Answer:

E= 6.45

standard deviation is σ = 15,

The critical value is z(α/2) = 2.58.

Step-by-step explanation:

Margin error is the value that is lie above and below the sample.It gives percentage of numbers.Its is the product of critical value standard deviation and standard error of statistic.

General formula for the margin of error is

Margin of error = critical value  ×   standard error of statistic

                        = z \alpha /2  ×   σ √n

z-value from two tailed is listed below:

From the table of standard normal distribution, probability value of 0.10.

row and column values gives the area to the two tail of z.

The positive z value is 2.58.

standard deviation is σ = 15,

The critical value is z(α/2) = 2.58.

after putting these vales we obtain the margin of error value that is

E= 6.45

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The 11% statement is extra information.

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