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hram777 [196]
1 year ago
6

A car accidentally rolls off cliff as it leaves the cliff it has a horizontal velocity of 13 m/s it hits the ground 60 m from th

e shoreline calculate the height of the cliff
Physics
1 answer:
nasty-shy [4]1 year ago
6 0

Answer:

h = 104.13 m

Explanation:

Given that,

Horizontal velocity of the car, v = 13 m/s

It hits the ground 60 m from the shoreline

We need to find the height of the cliff. Let t be the time of fall. We can find it as follows :

t=\dfrac{d}{v}\\\\t=\dfrac{60\ m}{13\ m/s}\\\\t=4.61\ s

So, the time of fall is 4.61 seconds.

Let h is the height of the cilff. Using second equation of motion to find it as follows :

h=\dfrac{1}{2}gt^2\\\\h=\dfrac{1}{2}\times 9.8\times 4.61^2\\\\=104.13\ m

So, the height of the cliff is 104.13 m.

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2 years ago
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A cat is sleeping on the floor in the middle of a 3.0-m-wide room when a barking dog enters with a speed of 1.50 m/s. as the dog
kondor19780726 [428]
Good morning.


Lets make the movement function for the dog and cat.

The cat has a start position of1.5 m(the middle of the room), with an initial speed of 0 and acceleration of 0.85 m/s².

The dog has a start position of 0, an initial speed of 1.5 m/s and acceleration of -0.1 m/s².


<u>Cat:</u>

\mathsf{X = X_0+V_0t + \dfrac{at^2}{2}}\\ \\ \mathsf{X = 1.5 + \dfrac{0.85t^2}{2}}\\ \\ \\ \mathsf{X_c = 1.5 + 0.425t^2}

<u>Dog:</u>

\mathsf{X_d= 1.5t - 0.05t^2}


Let's see if the dog reach the cat. Physically, it means \mathsf{X_d = X_c}

\mathsf{1.5t - 0.05t^2 = 1.5 + 0.425t^2}\\ \\ \mathsf{0.425t^2 + 0.05t^2 - 1.5t + 1.5 = 0}\\ \\ \mathsf{0.475t^2 - 1.5t + 1.5=0}

Now we solve for <em>t</em>:

\mathsf{\Delta = (-1.5)^2 - 4\cdot0.475\cdot1.5}\\ \\ \mathsf{\Delta = 2.25-2.85=-0.6 \ \textless \  0}

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6 0
2 years ago
In Part 6.2.2, you will determine the wavelength of the laser by shining the laser beam on a "diffraction grating", a set of reg
harkovskaia [24]

Answer:

λ = 2042 nm

Explanation:

given data

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spot s = 4.5 cm = 4.5 ×10^{-2} m

separation L = 0.5 mm = 0.5 ×10^{-3} m

to find out

what is λ

solution

we will find first angle between first max and central bright

that is tan θ = s/d

tan θ = 4.5 ×10^{-2}  / 11

θ = 0.234

and we know diffraction grating for max

L sinθ  = mλ

here we know m = 1  so put all value and find λ

L sinθ  = mλ

0.5 ×10^{-3}  sin(0.234)  = 1 λ

λ = 2042.02 ×10^{-9}  m

λ = 2042 nm

3 0
2 years ago
A 6.0-cm-diameter, 11-cm-long cylinder contains 100 mg of oxygen (O2) at a pressure less than 1 atm. The cap on one end of the c
g100num [7]

Explanation:

The given data  is as follows.

Mass of oxygen present = 100 mg = 100 \times 10^{-3} g

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         = 3.125 \times 10^{-3} moles

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Length of tube = 11 cm = 0.11 m

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Now, we assume that the inside pressure is P .

And,   P_{atm} = 100 kPa = 100000 Pa,

Pressure difference = 100000 - P

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      Force = Pressure difference × A

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We are given that force is 173 N.

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         (100000 - P) \times 2.82 \times 10^{-3} = 173

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6 0
2 years ago
A research group at Dartmouth College has developed a Head Impact Telemetry (HIT) System that can be used to collect data about
Olin [163]

Answer:

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Explanation:

The given equation is

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So we can wind the stopping distance by following formula

2 (-1000)(x-x₀)=[0^{2} -11^{2}]

x-x₀=6.05*10^{-2} m

       =6.05 cm

3 0
1 year ago
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