Answer:
–90 < –32t – 10 < –58
Step-by-step explanation:
We want the velocity to be BETWEEN -90 and -58.
Whenever we need a quantity, let it be A, to be between two numbers, p and q (p is less than q), we can write it as:
p < A < q
Similarly, here we need the velocity, -32t-10 to be BETWEEN -90 and - 58 (with -90 being the smaller number). Thus we can write:
–90 < –32t – 10 < –58
This is the correct choice, 2nd choice.
as far as I can tell, is just a matter of going around the circle many or infinite times around.
so 6,31° is the first point, the next point will be one-go-around, 6, 31+360 => 6, 391°
then the next will be 6, 391+360 => 6, 751° and so on.
so we can say is (6, 31° ±360°n), n ∈ ℤ.
1/8 ( 8x + 15)= 24
x + 1 7/8= 24
x= 24 - 1 7/8
x= 22 1/8
The answer is none of them.
Answer:
The confidence interval for the difference in proportions is

No. As the 95% CI include both negative and positive values, no proportion is significantly different from the other to conclude there is a difference between them.
Step-by-step explanation:
We have to construct a confidence interval for the difference of proportions.
The difference in the sample proportions is:

The estimated standard error is:

The z-value for a 95% confidence interval is z=1.96.
Then, the lower and upper bounds are:

The confidence interval for the difference in proportions is

<em>Can it be concluded that there is a difference in the proportion of drivers who wear a seat belt at all times based on age group?</em>
No. It can not be concluded that there is a difference in the proportion of drivers who wear a seat belt at all times based on age group, as the confidence interval include both positive and negative values.
This means that we are not confident that the actual difference of proportions is positive or negative. No proportion is significantly different from the other to conclude there is a difference.
This is a pretty bad question but I think the answer they're looking for is
angle
circle
line segment
We define arcs in terms of circles and parallel lines in terms of lines (though not necessarily line segments, so this is a bit of a judgement call).