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2 years ago

Which orbital notation represents the second principal energy level of a silicon atom in the ground state?

Chemistry

1 answer:

kati45 [8]2 years ago

3 0

Answer:

Explanation:

Silicon is one the elements found in nature and well positioned the periodic table.

It has an atomic number of 14 with an electronic configuration:

1s² 2s² 2p⁶ 3s² 3p⁴

From this formula the orbital notation that represents the second principal energy level is 2.

The main energy level in which the orbital is located or the average distance of the orbital from the nucleus is the principal quantum number.

It takes the number 1,2,3,4,5 e.t.c

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Fe3+(aq)+6H2O(l)⇌Fe(H2O)63+(aq) : F e 3 + ( a q ) + 6 H 2 O ( l ) ⇌ F e ( H 2 O ) 6 3 + ( a q ) : blank is the Lewis acid and bl

Tasya [4]

Answer:

Lewis acid- Fe3+

Lewis base- water molecule

Explanation:

Acids and bases have been defined in diverse ways. There have been definitions put forward by Arrhenius, Brownstead and Lowry as well as Lewis. Each definition his useful in its own way.

Lewis acids are lone pair acceptors such as metal ions. This implies that in the particular instance of this reaction, Fe3+ is the lewis acid.

Similarly, a Lewis base is a lone pair donor, all ligands are lone pair donors since they donate one or more lone pairs of electrons to Lewis acids. In the particular instance of this reaction, the Lewis base is the water molecule.

6 0

2 years ago

HELP HELP ASAP<br> I WILL MARK BRAINLIEST

likoan [24]

Answer:

i cant read it

Explanation:

6 0

2 years ago

2. If a machine produces 225 parts in an 8 hour day, how many minutes will it take to

vekshin1

21.28s

Explanation:

This is a rate problem.

Number of parts produced = 225

Time taken to produce= 8hours

Rate of production is the amount of parts produced in a duration of time.

Now convert 8 hours to minute;

60 minutes = 1hr

8 hours = 60 x 8 = 480minutes

Now:

Rate of production = $\frac{225 parts}{480min}$ = 0.47parts/minute

Now, to produce 10 parts;

It takes;

0.47 parts to be produced in 1 minute

10 parts would be produced in $\frac{10}{047}$ = 21.28s

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4 0

2 years ago

In a certain city, electricity costs $0.17 per kW·h. What is the annual cost for electricity to power a lamp-post for 5.50 hours

Anon25 [30]

Answer:

(a) = $34.123

(b) = $8.532

Explanation:

Cost of electricity = $0.17 per kW·h

(a) For a 100 watt bulb which is the same as 100/1000 or 0.1 kW, the cost per hour =

0.1 × 0.17 = $0.017/h

and for 5.5 hours = 0.017×5.5 = $0.0935

The annual cost, which is 365 days, we have

Annual cost = $0.0935 × 365 = $34.123

(b) For the energy efficient 25-watt bulb, we have

25/1000 = 0.025kW

Power cost per annum =

0.025kW×$0.17 per kW·h×5.5×365 = $8.532

Total cost of using the energy efficient fluorescent bulb is about $3.49

Total cost of using the energy efficient bulb = $8.532 + $3.49 = $12.02

Total cost of incandescent bulb = $35.02 while total cost of energy efficient bulb is = $12.02

$12.02 <$35.02

Additional cost of fluorescent bulb is justified

8 0

2 years ago

An evaporation–crystallization process of the type described in Example 4.5-2 is used to obtain solid potassium sulfate from an

timofeeve [1]

Answer:

feed = 220.77 kg/s; maximum production rate of solid crystal = 416 kg/s; the rate of supplying fresh feed to obtain the production rate = 1.6

Explanation:

Material or mass balance can be used to estimate the mass flow rates of all the streams in the diagram shown in the attached file.

Overall balance: $M_{1} = 175 + 11M_{2}$

Water: $0.804M_{1} = 175 + 0.6M_{2}$

Using substitution method, we have:

$M_{1}$ = 220.77 kg/s

$M_{2}$ = 4.16 kg/s

The maximum production rate of solid crystal is $10M_{2}$ = 10*4.16 = 416 kg/s

Around evaporator:

$0.45M_{5} = 175$

$M_{5} = 175/0.45 = 389$ kg/s

Around the mixing point:

$M_{1} + M_{3} = M_{4} + M_{5}$

Solid crystal: $0.196M_{1} + 0.4M_{3} = M_{4}$

Using the last two equations, we can obtain:

$0.804M_{1} + 0.6M_{3} = M_{5}$

$0.6M_{3} = 389 - 0.804*220.77 = 389 - 177.5 = 211.5$

$M_{3} = 211.5/0.6 = 352.5$ kg/s

The rate of supplying fresh feed to obtain the production rate is:

$\frac{M_{3}}{M_{1}}$ = 352.5/220.77 = 1.6

7 0

3 years ago