All categories

2 years ago

If the product of two rational numbers is (-9/16) and one of them is (-4/15) find the other number.

Mathematics

1 answer:

ololo11 [35]2 years ago

8 0

Given:

The product of two numbers is (-9/16).
One of the numbers is (-4/15)

To find: The other number.

Answer:

Let's assume the unknown number to be 'x'.

(-4/15) × x = (-9/16)

× = (-9/16) ÷ (-4/15)

When we divide a fraction by another fraction, the divisor will be taken in its reciprocal form.

x = (-9/16) × (-15/4)

x = 135/64

Therefore, the other number is 135/64.

Hope it helps. :)

You might be interested in

A circle with radius of \greenD{4\,\text{cm}}4cmstart color #1fab54, 4, start text, c, m, end text, end color #1fab54 sits insid

mario62 [17]

Answer:

The area of the shaded region is $329.87\ cm^2$

Step-by-step explanation:

The correct question is

A circle with radius of 4cm sits inside a circle with a radius of 11cm. What is the area of the shaded region?

The shaded region is the area outside the smaller circle and inside the larger circle

we know that

To find out the shaded region subtract the area of the smaller circle from the area of the larger circle

$A=\pi r_a^{2} -\pi r_b^{2}$

simplify

$A=\pi (r_a^{2} -r_b^{2})$

where

r_a is the radius of the larger circle

r_b is the radius of the smaller circle

we have

$r_a=11\ cm\\r_b=4\ cm$

substitute

$A=\pi (11^{2} -4^{2})$

$A=\pi (105)\ cm^2$

assume

$\pi=3.1416$

substitute

$A=(3.1416)(105)=329.87\ cm^2$

7 0

2 years ago

Which polynomials are prime? Check all that apply. 2x2+ 7x + 1 5x2 – 10x + 5 3x2 + 8 4x2 – 25 x2 + 36

aleksley [76]

The correct answer would be 2x2+ 7x + 1, 3x2 + 8 and x2 + 36. These polynomials cannot be reduced to a lower degree where the factors are integers so they should be prime. The factors are as follows:

2x2+ 7x + 1 -0.1492189406 and -3.350781059
5x2 – 10x + 5 1 and 1
3x2 + 8 1.632993162i and - 1.632993162i
4x2 – 25 5/2 and -5/2
x2 + 36 6i and -6i

6 0

2 years ago

Read 3 more answers

A line segment has endpoints at (–1, 4) and (4, 1). Which reflection will produce an image with endpoints at (–4, 1) and (–1, –4

katrin2010 [14]

Answer:- A reflection of the line segment across the line y = –x .

Explanation:-

A reflection over the line y = -x, the x-coordinate and y-coordinate interchange their places and they are negated (the signs are changed).

Given :- A line segment has endpoints at (–1, 4) and (4, 1) such that it reflects produce an image with endpoints at (–4, 1) and (–1, –4).

(-1, 4)→(-4, 1) and

(4, 1)→(-1, -4)

Thus this shows a reflection of the line segment across the line y = –x.

4 0

2 years ago

Read 2 more answers

H(x)=5x-1h(x)=5x−1, find h(1)h(1

lisabon 2012 [21]

Answer:

Solve f(x)=6x-12 g(x)=5x+1 h(x)=x^2-4 (f+g)(x). f(x)=6x−12 f ( x ) = 6 x - 12 g(x)=5x+1 g ( x ) = 5 x + 1 h(x)=x2−4 h ( x ) = x 2 - 4 (f+g)(x) ( f + g ) ( x ). Evaluate f+g f + ...

Step-by-step explanation:

Solve f(x)=6x-12 g(x)=5x+1 h(x)=x^2-4 (f+g)(x). f(x)=6x−12 f ( x ) = 6 x - 12 g(x)=5x+1 g ( x ) = 5 x + 1 h(x)=x2−4 h ( x ) = x 2 - 4 (f+g)(x) ( f + g ) ( x ). Evaluate f+g f + ...

7 0

2 years ago

Exercise 5.6.6: Selecting a committee of senators. About A country has two political parties, the Demonstrators and the Repudiat

krok68 [10]

Answer:

There are 4,148,350,734,528 ways

Step-by-step explanation:

We have

44 senators which are Demonstrators.
56 senators which are Repudiators.

(a) How many ways are there to select a committee of 10 senate members with the same number of Demonstrators and Repudiators?

We want to choose 5 Demonstrators and 5 Repudiators. The number of ways to do this is ${44} \choose {5}$ and $56 \choose 5$ respectively. Therefore, the number of ways to select the committee is given by:

${{44}\choose {5}} \times {{56}\choose{5}}=\frac{44!}{39!5!}\times\frac{56!}{51!5!}=\frac{44!56!}{51!39!5!5!}=\frac{44\times43\times42\times41\times40\times56\times55\times54\times53\times52}{5!5!}=\\\\=\frac{44\times43\times42\times41\times8\times56\times11\times54\times53\times52}{4!4!}= \frac{11\times43\times42\times41\times2\times56\times11\times54\times53\times52}{3!3!}=\\\\\frac{11\times43\times14\times41\times2\times56\times11\times18\times53\times52}{2!2!}=$

$11\times43\times14\times41\times28\times11\times18\times53\times52=4,148,350,734,528$

(b) Suppose that each party must select a speaker and a vice speaker. How many ways are there for the two speakers and two vice speakers to be selected?

If the speaker and vice speaker are chosen between all senators: In this case, the answer will be

$44\times43\times56\times55=5,827,360.$

This is because there are (in the case of Demonstrators) 44 possibilities to choose an speaker and after choosing one, there would be 43 possibilities to choose a vice speaker. The same situation happens in the case of Repudiators.

If the speaker and vice speaker are chosen between the committee: In this case, the answer will be

$5\times4\times5\times4=400$ .

3 0

2 years ago

If the product of two rational numbers is (-9/16) and one of them is (-4/15) find the other number.​

If the product of two rational numbers is (-9/16) and one of them is (-4/15) find the other number.