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nadya68 [22]
1 year ago
10

3.) AI 65 kom hr. Alfred can reach home in 50 minutes. At what speed should he drive his car

Mathematics
1 answer:
Yanka [14]1 year ago
8 0

Answer:

He should drive his car at a speed of 81.25 kilometers per hour.

Step-by-step explanation:

With a velocity of 65 kilometers per hour, he reaches home in 50 minutes. What speed he needs to reach home 10 minutes earlier, that is, in 50 - 10 = 40 minutes?

To solve this, we use the relation between inverse proportion variables(as the velocity increases, time needed decreases), that is, a rule of three with line multiplication, instead of cross. So

65 kilometers per hour - 50 minutes

x kilometers per hour - 40 minutes

So

40x = 65*50

x = \frac{65*50}{40}

x = 81.25

He should drive his car at a speed of 81.25 kilometers per hour.

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manny's cleaning supply store receives a mixture of 80% detergent and 20% water in 15 gallon buckets. manny would like a mixture
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1.25

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SunshineMadison101

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The manager suggests that Darryl should purchase the deli’s bread from Store D because they sell the most loaves of bread for th
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Step-by-step explanation:

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5 0
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Read 2 more answers
The random variable X, representing the number of cherries in a cherry puff, has the following probability distribution:x: 4 - 5
marta [7]

Answer:

Step-by-step explanation:

Given is the probability distribution of a random variable X

X 4 5 6 7 Total

P 0.2 0.4 0.3 0.1 1

x*p 0.8 2 1.8 0.7 5.3

x^2*p 3.2 10 10.8 4.9 28.9

a) E(X) = Mean of X = sum of xp = 5.3

Var(x) = 28.9-5.3^2=0.81

Std dev = square root of variance = 0.9

------------------------------------

b) For sample mean we have

Mean = 5.3

Variance = var(x)/n = \frac{0.81}{{36} } \\=0.0225

c) P(\bar X

3 0
2 years ago
Tan 235° = 2tan20°+ tan215°​
Mariulka [41]

Given :  tan 235 = 2 tan 20 + tan 215

To Find : prove that

Solution:

tan 235 = 2 tan 20 + tan 215

Tan x = Tan (180 + x)

tan 235 = tan ( 180 + 55) = tan55

tan 215 = tan (180 + 35) = tan 35

=> tan 55 = 2tan 20 + tan 35

55 = 20 + 35

=> 20  = 55 - 35

taking Tan both sides

=> Tan 20 = Tan ( 55 - 35)

=> Tan 20  = (Tan55 - Tan35) /(1 + Tan55 . Tan35)

Tan35 = Cot55 = 1/tan55 => Tan55 . Tan35 =1

=> Tan 20  = (Tan 55 - Tan 35) /(1 + 1)

=> Tan 20  = (Tan 55 - Tan 35) /2

=> 2 Tan 20  = Tan 55 - Tan 35

=> 2 Tan 20 +  Tan 35 = Tan 55

=>  tan 55 = 2tan 20 + tan 35

=>  tan 235 = 2tan 20 + tan 215

QED

Hence Proved

5 0
2 years ago
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