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HACTEHA [7]
1 year ago
8

29, 58,116, Find the 7th term.

Mathematics
1 answer:
prohojiy [21]1 year ago
5 0

9514 1404 393

Answer:

  1856

Step-by-step explanation:

The numbers given do not have a common difference, but they do have a common ratio:

  58/29 = 116/58 = 2

The general term of a geometric sequence with first term a1 and common ratio r is ...

  an = a1×r^(n-1)

For this sequence, a1=29 and r=2, so the general term is ...

  an = 29×2^(n-1)

Then the 7th term is ...

  a7 = 29×2^(7-1) = 29×64 = 1856

The 7th term is 1856.

_____

If you prefer, you can double each term until you have 7 of them.

 29, 58, 116, 232, 464, 928, 1856, ...

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2 years ago
your friend deposits $9500 in an investment account that earns 2.1% annual interest. what is the balance after 11 years when the
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2 years ago
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d = √[(2 - 4)² + (3 - (-3))²]

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