All categories

1 year ago

What are the correct coefficients when this chemical equation is balanced? * P4 + 02 P2O5

Chemistry

1 answer:

finlep [7]1 year ago

3 0

Answer:

What are the correct coefficients when this chemical equation is

balanced? *

P4 + 02 P2O5

Explanation:

For this reaction we have a combination reaction. Balancing Strategies: This combination reaction is a lot easier to balance and if you can get an even number of oxygen atoms on the reactants side of the equation.

You might be interested in

Sodium reacts with chlorine gas according to the following reaction: 2Na(s)+Cl2(g)→2NaCl(s) What volume of Cl2 gas, measured at

asambeis [7]

Answer:6.719Litres of Cl2 gas.

Explanation:According to eqn of rxn

2Na +Cl2=2NaCl

P=689torr=689/760=0.91atm

T=39°C+273=312K

according to stoichiometry of the reaction,1Moles of Cl2 gives 2moles of NaCl

But 28g of NaCl was given,we have to convert this to moles by using the relation, n=mass/MW

MW of NaCl=23+35.5=58.5g/mol

n=28g(mass given of NaCl)/58.5

n=0.479moles of NaCl

Going back to the reaction,

if 1moles of Cl2 produces 2moles of NaCl

x moles of Cl2 will give 0.479moles of NaCl.

x=0.479*1/2

x=0.239moles of Cl2.

To find the volume, we use ideal ggas eqn,PV=nRT

V=nRT/P

V=0.239*0.082*312/0.91

V=6.719Litres

6 0

2 years ago

Amy performed an experiment in lab. She improperly mixed the chemicals, and an explosion of light, sound, and heat occurred. Whe

agasfer [191]

The answer is D transformed

4 0

2 years ago

The percent composition by mass of a compound is 76.0% c, 12.8% h, and 11.2% o. the molar mass of this compound is 284.5 g/mol.

Leokris [45]

You have a few steps to solve this one. First, we'll find the molar mass by percentage of each element in the molecule. Then, we'll divide each of those relative masses by the atomic mass of each element. The number of times the mass divides into the relative mass is the number of atoms of that element in the molecule:

C: 284.5 x .76 = 216.22
H: 284.5 x .128= 36.416
O: 284.5 x .112 = 31.864.

Now we divide out each element's atomic mass (from the periodic table). it's okay if they're approximated from the decimal answer.
C: 216.22 ÷ 12.011 ≈ 18
H: 36.416 ÷ 1.008 ≈36
O: 31.864 ÷ 15.999 ≈ 2

Therefore, the molecular formula is C18H36O2.

The empirical formula would be found by dividing out all factors of those subscript numbers. In our case, all of them can be divided by 2. The empirical formula would be C9H18O

7 0

2 years ago

How many moles of lead, Pb, are in 1.50 x 1012 atoms of lead?

SpyIntel [72]

Answer:

2.49*10⁻¹² mol

Explanation:

Use Avogadro's Number for this equation (6.022*10²³). Divide Avogrado's by the number of atoms you have to find moles. You are answer should be 2.49*10⁻¹² mol.

7 0

2 years ago

Read 2 more answers

SnO2 is reduced by carbon according to this reaction: SnO2 + C ???? Sn + CO2. How many liters of CO2 are produced if 300.0 grams

andrew-mc [135]

Explanation:

The given reaction is as follows.

$SnO_{2} + C \rightarrow Sn + O_{2}$

a). Molar mass of $SnO_{2}$ is [(mass of Sn) + (2 × mass of O)].

Therefore, molar mass of $SnO_{2}$ = (118.7 + 2 × 16) g/mol = 150.7 g/mol

Since, it is known that number of moles equal mass divided by molar mass. So, moles of Sn will be calculated as follows.

No. of moles = $\frac{mass}{molar mass of SnO_{2}}$

= $\frac{300 g}{150.7 g/mol}$

= 2.53 mol

As it is given that 1 mole of $SnO_{2}$ produces 1 moles of Sn and 1 moles of $CO_{2}$ . Hence, 2.53 moles of $SnO_{2}$ will also produce 2.53 moles of Sn and 2.53 moles of $CO_{2}$ .

Volume of 1 mole of $CO_{2}$ at STP is 22.4 L. Therefore, volume of 2.53 moles of $CO_{2}$ will be calculated as follows.

2.53 × 22.5 L = 56.67 L

Hence, 56.67 L of $CO_{2}$ are produced if 300.0 grams of tin are produced at STP.

b). Mass of tin is given as 1800.0 g. So, number of moles will be calculated as follows.

No. of moles = $\frac{mass}{molar mass of tin}$

= $\frac{1800.0 g}{118.7 g/mol}$

= 15.2 moles

As 15.2 moles of $SnO_{2}$ produces 15.2 moles of Sn. Therefore, weight of $SnO_{2}$ will be calculated as follows.

Mass = no. of moles × molar mass of $SnO_{2}$

= 15.2 moles × 150.7 g/mol

= 2290.64 g

Hence, 2290.64 grams of $SnO_{2}$ are required to produce 1800.0 grams of tin.

c). Mass of carbon given is 100.0 grams.

No. of moles = $\frac{mass}{molar mass of carbon}$

= $\frac{100 g}{12 g/mol}$

= 8.33 moles

As, 1 mole of carbon is produced by 1 mole of tin. So, 8.33 mole of carbon will be produced by 8.33 moles of tin.

Therefore, calculate mass of tin produced as follows.

Mass = no. of moles × molar mass of Sn

= 8.33 moles × 118.7 g/mol

= 988.8 g

Hence, 988.8 grams of tin will be produced per 100 grams of carbon used.

8 0

2 years ago