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SSSSS [86.1K]
1 year ago
7

The table shows the blood pressures of 16 clinic patients. What is the interquartile range of the data?

Mathematics
1 answer:
Alex73 [517]1 year ago
5 0
I’ve attached my work below....
I ran out of space so the step 5 the last step is subtract q1 and q3 which step 3 and 4
So 90.9-81.8=9.1

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What is the missing step in solving the inequality 5 – 8x < 2x + 3? Add 2x to both sides of the inequality. Subtract 8x from
kvasek [131]

Answer:

⇒ Add 8x to both sides of the inequality

⇒ x>1/5

Step-by-step explanation:

First, you subtract by 5 from both sides of equation.

5-8x-5<2x+3-5

Solve.

-8x<2x-2

Then subtract by 2x from both sides of equation.

-8x-2x<2x-2-2x

Solve.

-10x<-2

Multiply by -1 from both sides of equation.

(-10x)(-1)>(-2)(-1)

Solve.

10x>2

Divide by 10 from both sides of equation.

10x/10>2/10

Solve to find the answer.

2/10=10/2=5 2/2=1=1/5

x>1/5 is final answer.

Hope this helps!

5 0
2 years ago
Read 2 more answers
The table shown represents the details of a car loan.
horrorfan [7]

Answer:

The Finance Amount for 36 months for the purchased of car is $7,478

Step-by-step explanation:

Given as for the Carl loan :

The cost of car = $ 11,578

The down payment of car = $4,100

So, The amount on which loan sanctioned = $ 11,578 - $ 4,100 = 7,478

The time period of loan = 36 months = 3 years

So, The Finance Amount for 36 months = A =  $ 11,578 - $ 4,100 = 7,478

Hence The Finance Amount for 36 months for the purchased of car is $7,478  Answer

8 0
2 years ago
Read 2 more answers
Which table has a constant of proportionality between yyy and xxx of 0.60.60, point, 6?
Masteriza [31]

Answer:

B

Step-by-step explanation:

7 0
2 years ago
Each summer Primo Pizza and Pizza Supreme compete to see who has the larger summer profit. Let p(x) represent Primo Pizza's prof
Aleksandr [31]

Answer:

a)

i) p(x) = 1.4 s(x)

ii) s(x) = p(x) ÷ 1.4 = [p(x)]/1.4

b)

i) p(x) = [s(x) + 200]

ii) s(x) = [p(x) - 200]

c)

i) p(x) = s(x+4)

ii) s(x) = p(x-4)

Step-by-step explanation:

Complete Question

Each summer Primo Pizza and Pizza Supreme compete to see who has the larger summer profit. Let p(x) represent Primo Pizza's profit (in dollars) x days after June 1. Let s(x) represent Pizza Supreme's profit (in dollars) x days after June 1.

a) Suppose Primo Pizza's profit each day is 1.4 times as large as the profit of Pizza Supreme

i. Write a function formula for p using the function s.

ii. Write a function formula for s using the function p.

b) Suppose Primo Pizza's profit each day is $200 more than the profit of Pizza Supreme.

i) Write a function formula for p using the function s.

ii) Write a function formula for s using the function p.

c) Suppose Primo Pizza's profit on a given day is always the same as the profit of Pizza Supreme's profit 4 days later.

i) Write a function formula for p using the function s.

ii) Write a function formula for s using the function p.

The profits per day for Primo Pizza, x days after June 1 = p(x)

The profits per day for Supreme Pizza, x days after June 1 = s(x)

a) Primo Pizza's profits per day is 1.4 times that of Supreme Pizza's per day.

Primo Pizza's profits per day, x days after June 1 = p(x)

Supreme Pizza's profit per day, x days after June 1 = s(x)

i) p(x) = 1.4 s(x)

ii) s(x) = p(x) ÷ 1.4 = [p(x)]/1.4

b) Primo Pizza profits per day is $200 more than that of Supreme Pizza

Primo Pizza's profits per day, x days after June 1 = p(x)

Supreme Pizza's profit per day, x days after June 1 = s(x)

i) p(x) = [s(x) + 200]

ii) s(x) = [p(x) - 200]

c) Primo Pizza's profit on a given day is always the same as the profit of Pizza Supreme's profit 4 days later.

Primo Pizza's profits per day, x days after June 1 = p(x)

Supreme Pizza's profit per day, x days after June 1 = s(x)

Supreme Pizza's profit per day, 4 days later = s(x+4)

So,

i) p(x) = s(x+4)

ii) This means that Supreme Pizza's profit per day is the same as Primo Pizza's profit per day four days ago.

Primo Pizza's profit per day four days ago = p(x-4)

So,

s(x) = p(x-4)

Hope this Helps!!!

3 0
2 years ago
a(0.3−y)+1.1+2.4x (y−1.2) ​ =0 =−1.2(x−0.5) ​ Consider the system of equations above, where aaa is a constant. For which value o
Veseljchak [2.6K]

Answer:

For a = 1.22 there is one solution where y = 1.3

Step-by-step explanation:

Hi there!

Let´s write the system of equations:

a(0.3 - y) + 1.1 +2.4x(y-1.2) = 0

-1.2(x-0.5) = 0

Let´s solve the second equation for x:

-1.2(x-0.5) = 0

x- 0.5 = 0

x = 0.5

Now let´s repalce x = 0.5 and y = 1.3 in the first equation and solve it for a:

a(0.3 - y) + 1.1 +2.4x(y-1.2) = 0

a(0.3 - 1.3) + 1.1 + 2.4(0.5)(1.3 -1.2) = 0

a(-1) + 1.1 + 1.2(0.1) = 0

-a + 1.22 = 0

-a = -1.22

a = 1.22

Let´s check the solution and solve the system of equations with a = 1.22. Let´s solve the first equation for y:

1.22(0.3 - y) + 1.1 +2.4(0.5)(y-1.2) = 0

0.366 - 1.22y + 1.1 + 1.2 y - 1.44 = 0

-0.02y +0.026 = 0

-0.02y = -0.026

y = -0.026 / -0.02

y = 1.3

Then, the answer is correct.

Have a nice day!

4 0
2 years ago
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