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DIA [1.3K]
1 year ago
8

An infant acetaminophen suspension contains 80 mg/0.80 mL suspension. The recommended dose is 15 mg/kg body weight.

Chemistry
1 answer:
Brrunno [24]1 year ago
8 0

Answer:

0.8853 mL

Explanation:

First we <u>convert 13 lb to kg</u>, keeping in mind that <em>1 lb = 0.454 kg:</em>

  • 13 lb * \frac{0.454kg}{1lb} = 5.902 kg

Then we <u>calculate how many mg of acetaminophen should be given</u>, using the <em>recommended dose and infant mass</em>:

  • 15 mg/kg * 5.902 kg = 88.53 mg

Finally we<u> calculate the required mL of suspension</u>, using its <em>concentration</em>:

  • 88.53 mg ÷ (80 mg/0.80 mL) = 0.8853 mL
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What features of this model will help Armando answer the question?
Scrat [10]

Answer:

The adjustable legs and the table of sand.

<em>Note:The question is incomplete. The complete question is given below.</em>

Using Models to Answer Questions About Systems

Armando’s class was looking at images of rivers formed by flowing water. Most of the rivers were wide and shallow, but one river was narrow and deep. Armando’s class thinks that this river is narrow and deep because:

  • the hill that the water flowed down was very steep, or
  • the sand grains that the water flowed through were very small.

Armando designed the model below to try to answer the question: Why is this river so narrow and deep?

Explanation:

The model designed by Armando will be helpful to answer the question because of the following features it possesses:

1. An adjustable leg- since one of the hypotheses put forward by the class to explain why the river was narrow and deep was that the hill that the water flowed down was very steep, the adjustable legs can be lowered or raised in order to make the slope shallower or steeper so that their hypothesis can be tested.

2. A table of sand- the table of sand serves as the streambed. By adjusting the size of the sand grains to be larger or smaller, the students will be able to to test their second hypothesis that the small size sand grains that the water flowed through was the reason for the river to be narrow and deep.

The results of their experiments will enable them to come to a conclusion.

5 0
2 years ago
Read 2 more answers
A scientist is at the hospital visiting a friend's young daughter, who has been
slava [35]

Answer:

D

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The scientist identifies the need to make a drug to cure the respiratory illnesses.

5 0
2 years ago
When 0.610 g of titanium is combusted in a bomb calorimeter, the temperature of the calorimeter increases from 25.00 °C to 50.50
PtichkaEL [24]

Answer:

(ΔHrxn)= 0.15kJ/mol

Explanation:

(ΔHrxn) = mc∆t

=0.00061×9.84×(50.5-25)

= 0.153kJ/mol

8 0
2 years ago
SEP Use Models Why does the number of electrons in each principal energy shell increase as the number of the shell increases?
zlopas [31]

Answer:

See explanation

Explanation:

The number of electrons in each principal energy shell increases as the number of shells increases because more electronic orbitals become available to accommodate the electrons.

For instance, the n= 2 level only accommodates eight electrons in the s and p orbitals whereas the n=3 level accommodates 18 electrons in s, p and d orbitals respectively.

Each principal level accommodates 2n^2 electrons where n= the principal energy shell.

4 0
1 year ago
A sample of 0.6760 g of an unknown compound containing barium ions (ba2+) is dissolved in water and treated with an excess of na
notka56 [123]

Answer: 35.72 % of Barium ions will be present in the original unknown compound.

Explanation: The reaction of Barium ions and sodium sulfate is:

Na_2SO_4(aq.)+Ba^{2+}(aq.)\rightarrow BaSO_4(s)+2Na^+(aq.)

Here, Sodium sulfate is present in excess, Barium ions are the limiting reagent because it limits the formation of product.

Now, 1 mole of barium sulfate is produced by 1 mole of Barium ions.

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Molar mass of Barium ions = 137.327 g/mol

233.38 g/mol of barium sulfate will be produced by 137.323 g/mol of Barium ions, so

0.4105 grams of barium sulfate will be produced by = \frac{137.327g/mol}{233.38g/mol}\times 0.4105g of Barium ions

Mass of barium ions = 0.2415 grams

To calculate percentage by mass, we use the formula:

\% mass=\frac{\text{Mass of solute (in grams)}}{\text{Total mass of the solution(in grams)}}\times 100

Mass of the solution = 0.6760 grams

Putting the value in above equation, we get

\% \text{ mass of }Ba^{2+}\text{ ions}=\frac{0.2415g}{0.6760g}\times 100

% mass of Barium ions = 35.72%.

8 0
2 years ago
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