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ZanzabumX [31]
2 years ago
11

Complete the two acid dissociation reactions for the ethylenediammonium ion and select the correct symbol for the equilibrium co

nstant for each reaction.
Chemistry
1 answer:
murzikaleks [220]2 years ago
5 0

Answer:

Step 1:

N

H

+

3

C

H

2

C

H

2

N

H

+

3

(

a

q

)

⇌

A.

K

a

1

B.

K

a

2

C.

K

b

1

D.

K

b

2

Step 2:

N

H

2

C

H

2

C

H

2

N

H

+

3

(

a

q

)

⇌

A.

K

a

1

B.

K

a

2

C.

K

b

1

D.

K

b

2

Acid-

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Work= Fs

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A medical lab is testing a new anticancer drug on cancer cells. The drug stock solution concentration is 1.5×10−9m, and 1.00 ml
Elis [28]

The concentration of the drug stock solution is 1.5*10^-9 M i.e. 1.5 * 10^-9 moles of the drug per Liter of the solution

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8 0
2 years ago
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Consider the balanced equation below. 4NH3 + 3O2 --> 2N2 + 6H2O What is the mole ratio of NH3 to N2?
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ke prop to v^2


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