2 tablets 3x per say 14 day supply 15 tablets per bottle

Shelley receives supplies for her sno-cones business weekly. She usually works concession at four events a week and averages sal

My name is Ann [436]

Answer:

Shelley did not budget enough. She will need additional US$ 16 for fulfilling the average sales of 760 sno-cones at the 4 events. With the budget she has, she just can supply 714 sno-cones (250 / 0.35).

Step-by-step explanation:

1. Let's check all the information given for solving this question:

Cost of individual supply = US$ 0.35

Budget per week = US$ 250

Average sales of sno-cones per event = 190

Number of events per week = 4

2. Let's check if Shelley budgeted enough for the week events:

Total of sno-cones Shelley will sell = Average sales * Number of Events

Total of sno-cones Shelley will sell = 190 * 4 = 760

Cost of supplies for the week = Total of sno-cones * Cost of individual supply

Cost of supplies for the week = 760 * 0.35 = US$ 266

Budget per week = US$ 250

Budget per week - Cost of supplies for the week = 250 - 266 = - 16

Shelley did not budget enough. She will need additional US$ 16 for fulfilling the average sales of 760 sno-cones at the 4 events. With the budget she has, she just can supply 714 sno-cones (250 / 0.35).

4 0

2 years ago

The complement of 25% is 52% true or false

Anettt [7]

False; it would be 75%.

3 0

2 years ago

Read 2 more answers

a barangay has 1000 individuals and its population doubles every 60 years. Give an exponential model for the barangay's populati

sdas [7]

Answer:

P(t) = 1000e^(0.01155)t

Step-by-step explanation:

Let the population of barangay be expressed according to the exponential formula;

P(t) = P0e^kt

P(t) is the population of the country after t years

P0 is the initial population

t is the time

If barangay has 1000 initially, this means that P0 = 1000

If the population doubles after 60years then;

at t = 60, P(t) = 2P0

Substitute into the formula

2P0 = P0e^k(60)

2 = e^60k

Apply ln to both sides

ln2 = lne^60k

ln2 = 60k

k = ln2/60

k = 0.01155

Substitute k = 0.01155 and P0 into the expression

P(t) = 1000e^(0.01155)t

Hence an exponential model for barangay's population is

P(t) = 1000e^(0.01155)t

7 0

2 years ago

The true average diameter of ball bearings of a certain type is supposed to be 0.5 in. A one-sample t test will be carried out t

Naily [24]

Answer:

Option C - Do not reject the null hypothesis. There is not sufficient evidence that the true diameter differs from 0.5 in

Step-by-step explanation:

We are given;

n = 15

t-value = 1.66

Significance level;α = 0.05

So, DF = n - 1 = 15 - 1 = 14

From the one-sample t - table attached, we can see that the p - value of 0.06 at a t-value of 1.66 and a DF of 14

Now, since the P-value is 0.06,it is greater than the significance level of 0.05. Thus we do not reject the null hypothesis. We conclude that there is not sufficient evidence that the true diameter differs from 0.5 in.