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Veseljchak [2.6K]
1 year ago
10

terry wants to buy 3 eggplants. The eggplants weigh a total of 3 3/4 pounds. about how much will the eggplants cost?

Mathematics
1 answer:
Mrrafil [7]1 year ago
8 0

You are required to find the weight of each eggplant

The weight of each eggplant is 5/4 pounds

Let

Number of eggplant = 3

Total <em>Weight</em> of eggplant = 3 3/4 pounds

Weight of each eggplant = Total Weight of eggplant ÷ Number of eggplant

= 3 3/4 ÷ 3

= 15/4 ÷ 3

= 15/4 × 1/3

= (15 × 1) / (4 × 3)

= 15/12

= 5/4 pounds

Weight of each eggplant = <em>5/4 pounds</em>

Read more:

brainly.com/question/18549782

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Answer: 30 - 4 = 26

Step-by-step explanation:

30 - 2x = 0

so after 2 days he will have done 4 hours so 30 - 4 = 26

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Let Y denote a geometric random variable with probability of success p. a Show that for a positive integer a, P(Y &gt; a) = qa .
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Answer:

a) For this case we can find the cumulative distribution function first:

F(k) = P(Y \leq k) = \sum_{k'=1}^k P(Y =k')= \sum_{k'=1}^k p(1-p)^{k'-1}= 1-(1-p)^k

So then by the complement rule we have this:

P(Y>a) = 1-F(a)= 1- [1-(1-p)^a]= 1-1 +(1-p)^a = (1-p)^a = q^a

b) P(Y>a)= q^a

P(Y>b) = q^b

So then we have this using independence:

P(Y> a+b) = q^{a+b}

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Using the definition of conditional probability we got:

P(Y> a+b |Y>a)= \frac{P(Y> a+b \cap Y>a)}{P(Y>a)} = \frac{P(Y>a+b)}{P(Y>a)} = \frac{q^{a+b}}{q^a} = q^b = P(Y>b)

And we see that if a = 2 and b=5 we have:

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c) For this case we use independent identical and with the same distribution experiments.

And the result for part b makes sense since we are interest in find the probability that the random variable of interest would be higher than an specified value given another condition with a value lower or equal.

Step-by-step explanation:

Previous concepts

The geometric distribution represents "the number of failures before you get a success in a series of Bernoulli trials. This discrete probability distribution is represented by the probability density function:"

P(X=x)=(1-p)^{x-1} p

If we define the random of variable Y we know that:

Y\sim Geo (1-p)

Part a

For this case we can find the cumulative distribution function first:

F(k) = P(Y \leq k) = \sum_{k'=1}^k P(Y =k')= \sum_{k'=1}^k p(1-p)^{k'-1}= 1-(1-p)^k

So then by the complement rule we have this:

P(Y>a) = 1-F(a)= 1- [1-(1-p)^a]= 1-1 +(1-p)^a = (1-p)^a = q^a

Part b

For this case we can use the result from part a to conclude that:

P(Y>a)= q^a

P(Y>b) = q^b

So then we have this assuming independence:

P(Y> a+b) = q^{a+b}

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P(Y> a+b |Y>a)= \frac{P(Y> a+b \cap Y>a)}{P(Y>a)} = \frac{P(Y>a+b)}{P(Y>a)} = \frac{q^{a+b}}{q^a} = q^b = P(Y>b)

And we see that if a = 2 and b=5 we have:

P(Y> 2+5 | Y>2) = P(Y>5)

Part c

For this case we use independent identical and with the same distribution experiments.

And the result for part b makes sense since we are interest in find the probability that the random variable of interest would be higher than an specified value given another condition with a value lower or equal.

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Answer:

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third blank: increased

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Step-by-step explanation:

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The MAD of a set of data is the average distance between each data value and the mean. 400 is further than the mean than the MAD. This, increases the variability of the originally data set. As a consequence, the inclusion of 400 will result in a greater MAD

4 0
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