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ddd [48]
2 years ago
7

A ray of light is traveling from water into a diamond. Upon hitting the diamond, a light ray bends toward the normal. With this

information, what can you say about the speed of light as it passes from water into a diamond?
A.) the speed increases
B.) the speed decreases
C.) the speed drops to zero
D.) the speed does not change

The correct answer is B, the speed decreases
Physics
2 answers:
avanturin [10]2 years ago
4 0
The correct answer is b


Alexandra [31]2 years ago
3 0

Answer:

<u><em>The answer is</em></u>: <u>B.) the speed decreases</u>.

Explanation:

<em>When the light passes from one medium to another, its speed changes</em>.

<em>The light is affected by the medium it passes through, so that the denser the medium is</em>, the lower the speed of light. <em>When crossing a diamond, for example, which is a very dense medium</em>, the speed of light is reduced by a factor of 2,417.

<u><em>The answer is</em></u>: <u>B.) the speed decreases</u>.

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gaseous h2 and br2 are added to an evacuated 1.15L container kept at 298K. The intial partial pressurre of H2(g) is 0.782 atm an
Nastasia [14]

The partial pressures of HBr when the system reaches equilibrium is 2.4 X 10⁻¹¹ atm

<u>Explanation:</u>

H₂ + Br₂ ⇒ 2HBr

PH₂ = 0.782atm

PBr₂ = 0.493atm

Kp = (PHBr)²/ (PH₂) (PBr₂) = 1.4 X 10⁻²¹

At equilibrium:

Let 2x = pressure of HBr

PH₂ = 0.782 -x

PBr₂ = 0.493 - x

Kp = (2x)^2 / (0.782-x)(0.493-x)

Now, because Kp is very small, x will be very small compared to 0.782 and 0.493.

Then,

Kp = 1.4X10⁻²¹ = (4x²) / (0.782)(0.493)

x = 1.2X10⁻¹¹

PHBr = 2x = 2.4 X 10⁻¹¹ atm

Therefore, the partial pressures of HBr when the system reaches equilibrium is 2.4 X 10⁻¹¹ atm

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2 years ago
PLEASE ANSWER ACCURATELY DO NOT GUESS PLEASE AND THANK YOU
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Hello! I can help you with this!

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