Answer:
Explanation:
Since the front and back of the rocket simultaneously line up with forward and backward end of the platform respectively .
Then length of the platform = length of the train rocket .
A )
Time to cross a particular point on the platform
= length of rocket train / .96 x 3 x 10⁸
= 90 / .96 x 3 x 10⁸
= 31.25 x 10⁻⁸ s
B) Rest length of the rocket = length of platform = 90 m
C ) length of platform as viewed by moving observer =
= 
= 321 m
D ) For the observer on platform time taken = 31.25 x 10⁻⁸ s
for the observer in the rocket , time will be dilated so time recorded by observer in motion ,
8.75 x 10⁻⁸ s .
Answer:
468449163762.0812 W
Explanation:
m = Mass = 
V = Volume =
r = Distance of sphere from isotropic point source of light = 0.5 m
R = Radius of sphere = 2 mm
= Density = 19 g/cm³
c = Speed of light = 
A = Area = 
I = Intensity = 
g = Acceleration due to gravity = 9.81 m/s²
Force due to radiation is given by
According to the question
The power required of the light source is 468449163762.0812 W
Answer:
2014.44 N
Explanation:
mass of spacecraft, m = 1850 kg
distance r = 3 x R
where r be the radius of earth.
g be the acceleration due to gravity on the surface of earth and g' be the acceleration due to gravity at height
g' = g / 9
g' = 9.8 / 9 = 1.089 m/s²
Force of gravity on the space craft
F = m g' = 1850 x 1.089
F = 2014.44 N
Thus, the force of gravity on the space craft at height is 2014.44 N.
Answer:
Explanation:
The translational kinetic energy of the hoop is given by :
..................(1)
M is the mass of the hoop
v is the velocity of the hoop
The rotational kinetic energy of the hoop is given by :
Since, 
..............(2)
From equation (1) and (2) :
Therefore, the ratio of the translational kinetic energy to the rotational kinetic energy is 1.
Answer:
0.002925 m
Explanation:
Lt = LO(1 +α Δt ) here Lt is total length Lo is original length α is coefficient of linear expansion and Δt is change in temperature
<h2>for aluminium</h2>
α=25×10^-6
Lt = 5(1+25×10^-6×(70-20))
Lt = 5 (1+25×10^-6×50)
Lt = 5 ( 1+0.00125)
Lt = 5×1.00125
Lt =5.00625 m
<h2>for nickel </h2>
α=13.3×10^-6
Lt =5(1+13.3×10^-6×50)
Lt = 5(1+0.000665)
Lt =5.003325 m
hence difference in length =5.00625-5.003325
= 0.002925 m
