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Irina-Kira [14]
2 years ago
15

A point charge of 5.0 × 10–7 C moves to the right at 2.6 × 105 m/s in a magnetic field that is directed into the screen and has

a field strength of 1.8 × 10–2 T. What is the magnitude of the magnetic force acting on the charge? A. 0 N B. 2.3 × 10^–3 N C. 23 N D.2.3 × 10^11 N
The magnetic field 0.02 m from a wire is 0.1 T. What is the magnitude of the magnetic field 0.01 m from the same wire? A. 0.01 T B. 0.05 T C. 0.1 T D. 0.2 T
Physics
1 answer:
Over [174]2 years ago
9 0
1.) The formula for magnetic force is F = qvBsinθ.
Substituting, we have F=(5.0 × 10^–7 C) (2.6 × 10^5 m/s) (1.8 × 10^–2 T)(sin90°) [90° because point charge is perpendicular to magnetic field]

F = 2.34 x 10^-3 N
Answer is B.

2.) <span>The distance is reduced by 1/2, so B is twice or 0.2 T. Answer is D.</span>
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A 150 g particle at x = 0 is moving at 8.00 m/s in the +x-direction. As it moves, it experiences a force given by Fx=(0.850N)sin
krok68 [10]

Answer:

9.98 m/s

Explanation:

The force acting on the particle is defined by the equation:

F=(0.850) sin (\frac{x}{2.00}) [N]

where x is the position in metres.

The acceleration can be found by using Newton's second law:

a=\frac{F}{m}

where

m = 150 g = 0.150 kg is the mass of the particle. Substituting into the equation,

a=\frac{0.850}{0.150}sin (\frac{x}{2.00})=5.67 sin(\frac{x}{2.00}) [m/s^2]

When x = 3.14 m, the acceleration is:

a=5.67 sin(\frac{3.14}{2.00})=5.67 m/s^2

Now we can find the final speed of the particle by using the suvat equation:

v^2-u^2=2ax

where

u = 8.00 m/s is the initial velocity

v is the final velocity

a=5.67 m/s^2

x = 3.14 m is the displacement

Solving for v,

v=\sqrt{u^2+2ax}=\sqrt{8.00^2+2(5.67)(3.14)}=9.98 m/s

And the speed is just the magnitude of the velocity, so 9.98 m/s.

4 0
2 years ago
Which of the following statements best describes the characteristic of the restoring force in the spring-mass system described i
Grace [21]

Answer : The restoring force is directly proportional to the displacement of the block.

Explanation :

Restoring force is defined as the force that is exerted by the spring due to its mass.

Mathematically, the restoring force can be written as :

F\propto-x

F = - k x

where,

k is the spring constant.

x is the displacement caused due to the mass.

Negative sign shows that the force is acting in opposite direction.

So, it is clear that the restoring force is directly proportional to the displacement of the block.

Hence, the correct option is (b) " The restoring force is directly proportional to the displacement of the block ".

5 0
2 years ago
Read 2 more answers
3. A 75kg man sits at one end of a uniform seesaw pivoted at its center, and his 24kg son sits at the
bulgar [2K]

Answer:

The wife have to sit at 0.46 L from the middle point of the seesaw.

Explanation:

We need to make a sketch of the seesaw and the loads acting over it.

And by the studying of the Newton's law we can find the equation useful to find the distance of the mother sitting on the seesaw with respect to the center ot the pivot point.

A logical intuition will give us the idea that the mother will be on the side of her son to make the balance.

The maximum momentum with respect to the pivot point (0) will be:

M=75 *\frac{L}{2}

Where L/2 is the half of the distance of the seesaw

Therefore the other loads ( mom + son) must be create a momentum equal to the maximum momentum.

7 0
2 years ago
The two major problems with most motor vehicles are that they burn fossil fuels and _____________.
Citrus2011 [14]

Answer:

A. Create radioactive waste i believe

Explanation:

8 0
2 years ago
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A uniform magnetic field makes an angle of 30o with the z axis. If the magnetic flux through a 1.0 m2 portion of the xy plane is
Irina18 [472]

Answer:

(b) 10 Wb

Explanation:

Given;

angle of inclination of magnetic field, θ = 30°

initial area of the plane, A₁ = 1 m²

initial magnetic flux through the plane, Φ₁ =  5.0 Wb

Magnetic flux is given as;

Φ = BACosθ

where;

B is the strength of magnetic field

A is the area of the plane

θ is the angle of inclination

Φ₁ = BA₁Cosθ

5 = B(1 x cos30)

B = 5/(cos30)

B = 5.7735 T

Now calculate the magnetic flux through a 2.0 m² portion of the same plane

Φ₂ = BA₂Cosθ

Φ₂ = 5.7735 x 2 x cos30

Φ₂ = 10 Wb

Therefore, the magnetic flux through a 2.0 m² portion of the same plane is is 10 Wb.

Option "b"

3 0
2 years ago
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