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11Alexandr11 [23.1K]

2 years ago

3

The time it takes to travel a given distance varies inversely as the average rate of travel. averaging 42 miles per hour, it tak

es andre 5 hours to drive to donnegal. if it took him 4 hours and 20 minutes to reach donnegal on his last trip, what was his average rate of travel?

1 answer:

lana66690 [7]2 years ago

4 0

Your answer will be 50 mph

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Vikki [24]

1 isla thanks for your help and I hope you are feeling 44356

7 0

2 years ago

Small blocks, each with mass m, are clamped at the ends and at the center of a rod of length L and negligible mass. Compute the

fenix001 [56]

Answer:

Answered

Explanation:

a) Two balls are at a distance of L/2 from the axis of rotation and one block at the center. ( center of rod).

therefore,

$I=2\times m\frac{L}{2}^2$

$I= \frac{1}{2}mL^2$

b) two balls at a distance L/4 at the from the axis and 1 ball at a distance 3L/4 from the from the axis.

$I= 2\times m\times(L/4)^2 + m(\frac{3L}{4})^2$

= $\frac{1}{16} mL^2(2+9)= \frac{11}{16}mL^2$

5 0

2 years ago

Which statement best describes what energy transfer diagrams show? Energy can change form, but the total amount of energy stays

Rom4ik [11]

Energy can change form, but the total amount of energy stays the same.

3 0

2 years ago

Read 2 more answers

A sample of an unknown volatile liquid was injected into a Dumas flask (mflask = 27.0928 g, Vflask = 0.1040 L) and heated until

NNADVOKAT [17]

Answer:

The gas was Hexane

Explanation:

taking the diference between the mass of the flask and the final mass qe can calculate the mass of liquid injected (assuming none escaped the flask):

$m_{l} = 27.4593g - 27.0928g = 0.3665g$

with the volume of the flask we can get the density of the gas at the indicated pressure and temperature:

$d_{g} = \frac{0.3665 g}{0.1040L} = 3.524 g/L$

From the ideal gases law we have that the density can be calculated as:

$d_{g} = \frac{P*M}{R*T}$

Where R is the ideal gases constant = , and M the molecular weight of the fluid. Solving for M:

$M=\frac{d_{g}*R*T}{P}=\frac{3.524g/L*0,082atmL/molK*291K}{0.976atm}$

$M=86.16 g/mol$

Note that the temperature is computed in Kelvin T= 18+273=291K

The gas with the closer molar mass is Hexane

4 0

2 years ago

The sun transfers energy to the earth by radiation at a rate of approximately 1.00 kW per square meter of surface.

Mashutka [201]

Answer:

1320336992.2512 m²

1320.33 kilometers or 509.79 miles

Explanation:

Energy transferred by the sun

$W=0.24\times 1\times 10^3=240\ W/m^2$

Energy required by the United States is $1\times 10^{19}\ J/yr$ (assumed)

Power

$P=\frac{E}{t}\\\Rightarrow P=\frac{1\times 10^{19}}{365.25\times 24\times 3600}\\\Rightarrow P=316880878140.2895\ W$

Area

$A=\frac{P}{W}\\\Rightarrow A=\frac{316880878140.2895}{240}\\\Rightarrow A=132033699.2512\ m^2$

Area of the solar collector would be 1320336992.2512 m²

Converting to km²

$1\ m^2=\frac{1}{1000\times 1000}\ km^2$

$1320336992.2512\ m^2=1320336992.2512\times \frac{1}{1000\times 1000}\ km^2=1320.33\ km^2$

Converting to mi²

$1\ m^2=\frac{1}{1609.34\times 1609.34}\ mi^2$

$1320336992.2512\ m^2=1320336992.2512\times \frac{1}{1609.34\times 1609.34}\ mi^2=509.79\ mi^2$

Each side of the square would be 1320.33 kilometers or 509.79 miles

4 0

2 years ago