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ziro4ka [17]
2 years ago
6

Mr. Evans displays the test scores of his first period class in the box plot below.

Mathematics
2 answers:
ELEN [110]2 years ago
8 0

Answer:  Third option is correct.

Step-by-step explanation:

Since we have given that

1st Quartile of 3rd class period = 78

For 1st class period,

1st Quartile = 70

3rd Quartile = 85

IQR = Q₃-Q₁

IQR=85-70\\\\IQR=15

According to question,

IQR of 3rd class period is one - third of the IQR of 1st class period.

So, it becomes

IQR_3=\dfrac{1}{3}\times IQR_{1}\\\\IQR_3=\dfrac{1}{3}\times 15\\\\IQR_3=5

Now, we need to find the value of 3rd quartile of the scores from 3rd period.

IQR_3=Q_3-Q_1\\\\5=Q_3-78\\\\5+78=Q_3\\\\Q_3=83

Hence, Third option is correct.

valentinak56 [21]2 years ago
7 0
I think it is the last one, have a nice day!
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There are three choices of jellybeans - grape ,cherry and orange. if the probability of getting a grape is 3/10 and the probabil
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When looking at probabilities, two ideas are always true.

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Idea #2 works here. (For example, think of how a die has six things and the probability of each is 1/6. So 1/6 + 1/6 + 1/6 + 1/6 + 1/6 + 1/6 = 1.) Let G = the probability of grape, C = probability of cherry and O = the probability of orange. From Idea #2, G + C + O = 1. Since we know G and C, then

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2 years ago
A survey conducted five years ago by the health center at a university showed that 18% of the students smoked at the time. This
podryga [215]

Answer:

test statistic (Z) is 2.5767 and p-value of the test is .009975

Step-by-step explanation:

H_{0}: percentage of students who smoke did not change

H_{a}: percentage of students who smoke has changed

z-statistic for the sample proportion can be calculated as follows:

z=\frac{p(s)-p}{\sqrt{\frac{p*(1-p)}{N} } } where

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Then, z=\frac{0.25-0.18}{\sqrt{\frac{0.18*0.82}{200} } } ≈ 2.5767

What is being surveyed is if the percentage of students who smoke has changed over the last five years, therefore we need to seek two tailed p-value, which is .009975.

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Answer:

30°

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\frac{2}{Sin 30} = \frac{2}{Sin 30}

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6 0
2 years ago
A quality control engineer at a potato chip company tests the bag filling machine by weighing bags of potato chips. Not every ba
Ahat [919]

Answer:

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Step-by-step explanation:

Information provided

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Alternative hypothesis:p > 0.15  

The statistic for this case is:

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And replacing the info given we got:

z=\frac{0.21 -0.15}{\sqrt{\frac{0.15(1-0.15)}{100}}}=1.68  

5 0
2 years ago
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