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Lady_Fox [76]
2 years ago
13

Anna pushes a box with a force of 8.00 newtons. She generates a power of 3.00 watts. How much time does it take for Anna to move

the box the distance of 9.72 meters?
Physics
2 answers:
QveST [7]2 years ago
8 0
Power is the energy in a system per time.  It will have units of Watts which is equal to joules per second. It can be expressed as:

P = E / t

where E = Force x distance

P = Fd / t
t = Fd / P
t = 8 (9.72) / 3.0
t = 25.92 s
Ratling [72]2 years ago
8 0

Answer:

time taken, t = 25.92 seconds

Explanation:

It is given that,

Force acting on the box, F = 8 N

Power generated on the box, P = 3 watts

Distance traveled by the box, d = 9.72 m

We know that the power generated by an object is equal to the total work done divided by total time taken. Its formula is given by :

P=\dfrac{W}{t}

Since, W = F d

P=\dfrac{Fd}{t}

t=\dfrac{Fd}{P}

t=\dfrac{8\ N\times 9.72\ m}{3\ W}

t = 25.92 seconds

So, the time taken by Anna to move the box to the distance of 9.72 meters is 25.92 seconds. Hence, this is the required solution.

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The automobile has a weight of 2700 lb and is traveling forward at 4 ft>s when it crashes into the wall. If the impact occurs
alex41 [277]

Answer:

F_b=153918\, lb.ft.s^{-2}

Explanation:

Given:

mass, m=2700 \,lb

time, t=0.06\,s

velocity, v=4\,ft.s^{-1}

coefficient of kinetic friction between wheels & pavement, \mu=0.3

According to first condition,

F\times \Delta t=m\times v

F\times 0.06= 2700\times 4

F=180000\,lb.ft.s^{-2}

According to second condition,

<u>Magnitude of frictional force (which acts opposite to the direction of motion):</u>

f=\mu.N

where N is the normal reaction.

f=0.3\times 2700\times 32.2

f=26082 \,lb.ft.s^{-2}

Now, the impulsive force on the wall if the brakes were applied during the crash:

F_b= F-f

F_b=180000-26082

F_b=153918\, lb.ft.s^{-2}

3 0
2 years ago
What is a manifest function of a married father joining the military
katovenus [111]

Answer:

Explanation:

Manifest- he supports his family, fights for a living. He will support his family while he fights for a living it is basically his job. By fighting in war that is what income his family will get

6 0
2 years ago
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Which of the following selections completes the following nuclear reaction?
Monica [59]

Answer:

n (a neutron)

Explanation:

For a chemical element:

- The lower subscript indicates the atomic number (the number of protons)

- The upper subscript indicates the mass number (the sum of protons and neutrons in the nucleus)

In the reaction described in the problem, we see that a gamma photon hits a nucleus of Calcium-40, which has

Z = 20 (20 protons)

A = 40 (40 protons+neutrons)

Which means that the number of neutrons is n =  A - Z = 40 - 20 = 20

After the reaction, we have a nucleus of Calcium-39, which has

Z = 20 (20 protons)

A = 39 (39 protons+neutrons)

Which means that the number of neutrons is n =  A - Z = 40 - 39 = 19

So, the nucleus has lost 1 neutron, which is the particle missing in the reaction.

3 0
2 years ago
An owl has a mass of 4.00 kg. It dives to catch a mouse, losing 800.00 J of its GPE. What was the starting height of the owl, in
vesna_86 [32]

Answer:

height =20m

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gpe=mgh

800=4×10×x

40x=800

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3 0
2 years ago
14 gauge copper wire has a diameter of 1.6 mm. what length of this wire has a resistance of 4.8ω?
Vladimir79 [104]
The relationship between resistance R and resistivity \rho is
R= \frac{\rho L}{A}
where L is the length of the wire and A its cross section.

The radius of the wire is half the diameter:
r= \frac{d}{2}= \frac{1.6 mm}{2}=0.8 mm=8\cdot 10^{-4} m
and the cross section is
A=\pi r^2 = \pi (8\cdot 10^{-4} m)^2=2.01\cdot 10^{-6} m^2

From the first equation, we can then find the length of the wire when R=4.8 \Omega (copper resistivity: \rho = 1.724 \cdot 10^{-8} \Omega m)
L= \frac{AR}{\rho}= \frac{(2.01\cdot 10^{-6} m^2)(1.724 \cdot 10^{-8} \Omega m)}{4.8 \Omega}=7.21 \cdot 10^{-15} m
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2 years ago
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