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iogann1982 [59]
2 years ago
14

A box is sliding along a frictionless surface and gets to a ramp. Disregarding friction, how fast should the box be going on the

ground in order to slide up the ramp to a height of 2.5 meters, where it stops? (Use g = 9.8 m/s2.)
A) 2.2 m/s
B) 7.0 m/s
C) 9.9 m/s
D) 24 m/s
Physics
2 answers:
levacccp [35]2 years ago
9 0

This is amazing.  When you read the quest ion, you wouldn't think there's enough information there to find an answer.  But there is !

-- When the block is sliding along the flat surface, its kinetic energy is (1/2)(Mass·v²).

-- When it's 2.5m up the ramp and stops, its potential energy is (2.5m)·(Mass·g).

-- If there's no friction anywhere, these energies are equal.

(1/2)(Mass·v²)  =  (2.5m)·(Mass·g)

(v²/2) = (2.5m) · g

v² = 5m · g

v² = 49 m²/s²

<em>v = 7 m/s  </em>(B)

Nataly [62]2 years ago
6 0

Answer:

B: 7.0 m/s

Explanation:

on edge

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<span>h = 2.81 m</span>

<span>
</span>

<span>Therefore he has to climb 2.81 meters</span>

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Answer with Explanation:

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Answer:

See explanation below

Explanation:

As I say in the comments, the question is incomplete, however, I will try to answer this by using data that I found on another site.

This is the part of the question that is not here:

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