Answer:
Initial Velocity is 4 m/s
Explanation:
What is acceleration?
It is the change in velocity with respect to time, or the rate of change of velocity.
We can write this as:

Where
a is the acceleration
v is velocity
t is time
is "change in"
For this problem , we are given
a = 1.2
t = 10
Putting into formula, we get:

So, the change in velocity is 12 m/s
The change in velocity can also be written as:

It is given Final Velocity = 16, so we put it into formula and find Initial Velocity. Shown Below:

hence,
Initial Velocity is 4 m/s
Calculate the weight of the table through the equation,
W = mg
where W is the weight, m is the mass, and g is the acceleration due to gravity. Substituting the known values,
W = (0.44 kg)(9.8 m/s²)
<em>W = 4.312 N</em>
The components of this weight can be calculated through the equation,
Wx = W(sin θ)
and Wy = W(cos θ)
x - component:
Wx = W(sin θ)
Substituting,
Wx = (4.312 N)(sin 150°) = <em>2.156 N</em>
Wy = (4.312 N)(cos 150°) =<em> -3.734 N</em>
Answer:
The total mechanical energy does not change if the value of the mass is changed. That is, remain the same
Explanation:
The total mechanical energy of a spring-mass system is equal to the elastic potential energy where the object is at the amplitude of the motion. That is:
(1)
k: spring constant
A: amplitude of the motion = 2.0cm
As you can notice in the equation (1), the total mechanical energy of the system does not depend of the mass of the object. It only depends of the amplitude A and the spring constant.
Hence, if you use a mass of 0.40kg the total mechanical energy is the same as the obtained with a mas 0.20kg
Remain the same
with the same generator, so the only factor for producing
the slectric field is only the speed. The faster the rotational speed of the
generator the greater it produce electric field. So the sequence is 3000 rpm
< 3200 rpm < 3400 rpm < 3600 rpm
Answer:
18 times
Explanation:
According to the security purposes which is set under the rules and regulation OSHA, which describes all the rights to the worker.
In the boom hoist receiving system all the sheaves which are used should have a pitch diameter of rope not less than 18 times the diameter of the nominal rope which is used.