The mechanism will include
a) Slow step: rate determining step
In this step the leaving group (chloride ion) will leave the substrate and will form carbocation
b) Fast step:
The cation will be attacked by nucleophile and will give the substituted product
the mechanism is shown as :
Answer:
C The water had adequate nitrogen and phosphorus, so it is likely iron limited.
Explanation:
Phytoplankton are single- cell organisms that live in oceans.
They require nitrogen, phosphorus and trace amount of iron to survive.
From the scientist's results after testing the water for nitrogen and phosphorus,there are reasonable amount of these elements.
Therefore insufficient iron in the water is the reason why he could find plenty phytoplankton in the ocean.
Gravitational potential energy is observed when an object is not in rest or is in motion. In this case, the helicopter is in motion where the direction is going upward with a negative potential energy. Thank you for your question. Please don't hesitate to ask in Brainly your queries.
I think the answer is (4) different molecular structures and different properties. Both structure are crystal. The structure of graphite is organized in layers. And structure of diamond is a strong network of atoms. Also due to the different structures, they have different properties.
Missing table!! write the elements with the first letter of the symbol with Upper Caps letters!!!
http://www.chemeddl.org/services/moodle/media/QBank/GenChem/Tables/EStandardTable.htm
<span>Ni2+ +Pb(s) → Ni(s) + Pb2+
</span>The potential of the oxidation of Pb(s) --> Pb2+(aq) is 0.126 V
The potential of the reduction go Ni2+(aq) --> Ni(s) is -0.25 V
<span>Add the two together and the potential for the reaction is -0.124 V (NO SPONTANEOUS THE SIGN IS NEGATIVE)
</span><span>au3+ + al(s) → au(s) + al3+Au3+(aq) -> Au(s) +1.5 VAl -> Al3+ +1.66VV= 3.16 (SPONTANEOUS THE SIGN OF THE PONTENTIAL IS POSITIVE)</span><span>Sr2+ + Sn(s) → Sr(s) + Sn2+
</span>
Sr2+(aq) + 2 e– <span> Sr(s) V= -2.89V
</span>Sn -> Sn2+ V= 0.14 V
V= -2.75 V (no spontaneous)
<span>Fe2+ + Cu(s) → Fe(s) + Cu2+
</span>Fe2+(aq) + 2 e–<span> </span><span> Fe(s) V= -0.44 V
</span>Cu -> C2+ V = - 0.337V
V= - 0.777V (no spontaneous)
