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Scorpion4ik [409]
2 years ago
8

The graph shows the gravitational potential energy of a radio controlled toy helicopter.describe the motion of the toy

Chemistry
1 answer:
ICE Princess25 [194]2 years ago
6 0
Gravitational potential energy is observed when an object is not in rest or is in motion. In this case, the helicopter is in motion where the direction is going upward with a negative potential energy. Thank you for your question. Please don't hesitate to ask in Brainly your queries. 
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How many molecules are in 0.25 grams of dinitrogen pentoxide?
Vesna [10]
In order to get the answer, you have to know the formula of how to convert grams to mole and by that you can get the number of molecules.
The answer is 2 moles of N2O5. This is shown by the solution:
(0.25 g N2O5) (1 mol/ 108 g)=2.31 molecules
The answer is 2 molecules.
4 0
2 years ago
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16.34 g of CuSO4 dissolved in water giving out 55.51 kJ and 25.17 g CuSO4•5H2O absorbs 95.31 kJ. From the following reaction cyc
amm1812

Answer:

The enthalpy of hydration of copper sulphate is -1486.62 kJ/mol which means 1486.62kJ of energy is absorbed by one mole of copper sulphate during the process of hydration

Explanation:

Step 1: Determine the energy released per mole of CuSO_{4} dissolved

{CuSO_{4}}_{(s)} -> {CuSO_{4}}_{(aq)} (Eq. 1)

n_{CuSO_{4}} = \frac{m_{CuSO_{4}}}{M_{CuSO_{4}}}

n_{CuSO_{4}} = \frac{16.34}{159.5}

n_{CuSO_{4}} = 0.102 mol

If 0.102 moles of CuSO_{4} releases 55.51kJ of energy, 1 mole will release 541.85kJ/mol

{CuSO_{4}}_{(s)} -> {CuSO_{4}}_{(aq)} ΔH = -541.85kJ/mol

Step 2: Determine the energy released per mole of CuSO_{4}.5H_{2}O dissolved

{CuSO_{4}.5H_{2}O}_{(s)} -> {CuSO_{4}}_{(aq)}+{5H_{2}O}_{(l)} (Eq. 2)

n_{CuSO_{4}.5H_{2}O} = \frac{m_{CuSO_{4}.5H_{2}O}}{M_{CuSO_{4}.5H_{2}O}}

n_{CuSO_{4}.5H_{2}O} = \frac{25.17}{249.5}

n_{CuSO_{4}.5H_{2}O} = 0.101 mol

If 0.101 moles of CuSO_{4}.5H_{2}O absorbs 95.31kJ of energy, 1 mole will absorb 944.77kJ/mol

{CuSO_{4}.5H_{2}O}_{(s)} -> {CuSO_{4}}_{(aq)}+{5H_{2}O}_{(l)} ΔH = 944.77kJ/mol

Step 3: Subtracting Eq. 2 from Eq. 1

{CuSO_{4}}_{(s)} -> {CuSO_{4}}_{(aq)} ΔH = -541.85kJ/mol (Eq. 1)

{CuSO_{4}.5H_{2}O}_{(s)} -> {CuSO_{4}}_{(aq)}+{5H_{2}O}_{(l)} ΔH = 944.77kJ/mol (Eq. 2)

{CuSO_{4}}_{(s)} -{CuSO_{4}.5H_{2}O}_{(s)} -> {CuSO_{4}}_{(aq)} -{CuSO_{4}}_{(aq)}-{5H_{2}O}_{(l)} ΔH = -541.85-944.77

{CuSO_{4}}_{(s)}+{5H_{2}O}_{(l)} -> {CuSO_{4}.5H_{2}O}_{(s)} ΔH = -1486.62 kJ/mol

6 0
2 years ago
Define the following terms - you may need to consult your lecture text or other suitable resource:
natta225 [31]

Answer:

a) Monomers: monomers are unit molecules, that can react together with other monomers, to form a long chain molecule called a polymer. Th polymer formed can also be in a three dimensional network. The process of this conversion of monomers to polymers is called polymerization.

b) Repeating unit: A repeating unit is a unit of the polymer formed, whose repetition would produce a long complete polymer chain. A polymer is made up of these repeating links of molecules that form a long chain of molecules.

c) Condensation polymerization: This is a form of condensation reaction, that involves the combination of molecules into polymers with the loss of small molecules such as water or methanol as by products.

d) Cross-linked polymer: This is a polymer formed from a type of bonding of molecules. The bonding is usually in the form of covalent bonds or ionic bonds and the polymers can be either synthetic polymers or natural polymers.  The cross-links leads to an alteration in the physical properties of the polymer.

6 0
2 years ago
Andrew plays trumpet in the concert band. He holds the trumpet still at his side until it is time for him to play. When it is ti
Tom [10]

Answer:

Explanation:

The first law is An object won't move by itself, and once in motion, it won't stop unless some force acts upon it. With this being said when the trumpet is at his side and he is not holding it will not move not until he lets go of it.

6 0
2 years ago
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If 6.00 g of the unknown compound contained 0.200 mol of C and 0.400 mol of H, how many moles of oxygen, O, were in the sample?
Arada [10]

Convert moles to mass.

mass C = 0.2 mol * 12 g / mol = 2.4 g

mass H = 0.4 mol * 1 g / mol = 0.4 g

So mass left for O = 6 g – (2.4 g + 0.4 g) = 3.2 g

 

Calculating for moles O given mass:

moles O = 3.2 g / (16 g / mol) = 0.2 moles

 

Answer:

<span>0.2 moles O</span>

8 0
2 years ago
Read 2 more answers
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