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Firlakuza [10]
2 years ago
5

At a certain temperature, the reaction 2NO + Cl2 ⇌ 2NOCl has an equilibrium constant Kc of 45.0. A chemist creates a mixture wit

h the following initial concentrations: [NO] = 0.10 M, [Cl2] = 0.20 M, and [NOCl] = 0.30 M. What will happen as the reaction begins?
A. [NOCl] will increase.
B. [NOCl] will decrease.
C. [NOCl] will stay the same.
D. There is not enough information to answer the question.
Chemistry
1 answer:
Dmitriy789 [7]2 years ago
5 0

Answer:

C. [NOCl] will stay the same

Explanation:

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Consider the reaction H2(g) + Cl2(g) → 2HCl(g)ΔH = −184.6 kJ / mol If 2.00 moles of H2 react with 2.00 moles of Cl2 to form HCl,
zalisa [80]

Answer:

ΔU=-369.2 kJ/mol.

Explanation:

We start from the equation:

Δ(H)=ΔU+Δ(PV), which is an extension of the well known relation: H=U+PV.

If Δ(PV) were calculated by ideal gas law,

PV=nRT

Δ(PV)=RTΔn.

Where Δn is the change of moles due to the reaction; but, this reaction does not give a moles change (Four moles of HCl produced from 4 moles of reactants), so Δ(PV)=0.

So, for this case, ΔH=ΔU.

The enthalpy of reaction given is for one mole of reactant, so the enthalpy of reaction for the reaction of interest must be multiplied by two:

2 reactant moles*\frac{-184.6kJ}{mol}

ΔU=-369.2 kJ/mol.

4 0
2 years ago
The standard reduction potentials for two half-cells involving iron are: given below. Fe2+ (aq) + 2e– ® Fe (s) Eο = –0.44 V Fe3+
matrenka [14]

Answer:

Explanation:

Fe⁺² (aq) + 2e⁻ =   Fe (s)   ;   E⁰ =  - .44 V

Fe⁺³ (aq) + e⁻ =  ® Fe²⁺ (aq) ;   E⁰ = + .77 V

Reduction potential of second reaction is more , so it will take place , ie Fe⁺³ will be reduced and Fe will be oxidised .

So reaction in the combined cell will be

2Fe⁺³ + Fe = 3Fe⁺²

cell potential = .77 - ( - .44 )

= 1.21 V .

6 0
2 years ago
This is the chemical formula for nickel tetracarbonyl (a powerfully poisonous liquid used in nickel refining) Ni(CO)4 A chemical
OverLord2011 [107]

Answer : The number of moles of oxygen present in a sample are 11.3 moles.

Explanation :

The given compound is, Ni(CO)_4

By the stoichiometry we can say that, 1 mole of of Ni(CO)_4 has 4 moles of CO.

Or we can say that, 1 mole of of Ni(CO)_4 has 1 mole of nickel (Ni), 4 moles of carbon (C) and 4 moles of oxygen.

That means,

Number of moles of carbon = Number of moles of oxygen

As we are given that:

Number of moles of carbon = 11.3 moles

So, number of moles of oxygen = number of moles of carbon = 11.3 moles

Therefore, the number of moles of oxygen present in a sample are 11.3 moles.

7 0
2 years ago
Harvey kept a balloon with a volume of 348 milliliters at 25.0˚C inside a freezer for a night. When he took it out, its new volu
katrin2010 [14]

Answer:

T2=276K

Explanation:

Given:

Initial volume of the balloon V1 = 348 mL

Initial temperature of the balloon T1 = 255C

Final volume of the balloon V2 = 322 mL

Final temperature of the balloon T2 =

To calculate T1 in kelvin

T1= 25+273=298K

Based on Charles law, which states that the volume of a given mass of a ideal gas is directly proportional to the temperature provided that the pressure is constant. It can be applied using the below formula

(V1/T1)=(V2/T2)

T2=( V2*T1)/V1

T2=(322*298)/348

T2=276K

Hence, the temperature of the freezer is 276 K

8 0
2 years ago
Complete the following math problem and round your answer to the correct number of significant figures. Explain why your answer
BigorU [14]

Answer:

file link http/www.openfree

7 0
1 year ago
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