Answer:
It will take 4 sec rock to comes its original point
Explanation:
It is given that the rock comes to its original point
So displacement S = 0 m
Initial velocity u = 19.6 m/sec
Acceleration due to gravity
According to second equation of motion
t = 4 sec
Answer:
The rotational speed of the four smallest planets can be determined using the rotational speeds of the four largest planets and their orbital periods.
Explanation:
Kepler's three laws are:
1) The orbits of the planets around the Sun are ellipses, with the Sun at one of the focii
2) A line connecting the Sun with each planet sweeps out equal areas in equal time intervals
3) The cube of the semi-major axis of the orbit of one planet is proportional to the square of its orbital period
There 3 laws help explaining the following statements:
- <em>A planet's distance from the sun will not be the same in six months. --> </em>using the 1st law. In fact, since the orbit is an ellipse (and not a circle), and the Sun is at one of the focii, the distance of the planet from the Sun keeps changing during the year.
-<em> A planet's speed as it moves around the sun will not be the same in six months. -</em>-> using the 2nd law. In fact, since the line connecting the Sun to the planet must cover equal areas in the same time interval, it follows that the speed of the planet cannot be constant during the year (it will be faster when closer to the sun and slower when far from the sun).
- <em>The average distance of Saturn can be calculated using the average distance of Neptune and the orbital period of both planets. </em>--> using the 3rd law. In fact, the ratio (where a is the semi-major axis of the orbit and T the orbital period) is constant and it is the same for every planet orbiting the sun, so by knowing the data of Neptune and the orbital period of Saturn, it is possible to calculate Saturn's average distance.
Instead, the following statement:
<em>The rotational speed of the four smallest planets can be determined using the rotational speeds of the four largest planets and their orbital periods.</em>
Is not supported by any Kepler's law.