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2 years ago

Lim x tends to 0 sinax/tanbx

1 answer:

8 0

Express tan in terms of sin and cos

= sin ax cos bx / sin bx

Now I'm stuck! sorry

For what its worth Ive drawn the graph and the answer is a/b

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10 x 3 tens - unit form and standard form

vfiekz [6]

10X3 tens in unit form is written:
10*3 tens = 30 tens = 300 units

10X3 tens in standard form:
10 x 3 tens = 10 x 30 = 300

6 0

2 years ago

Read 2 more answers

Given E = I × R and P = E × I, select the formula that will solve for E when only R and P are known.

stiv31 [10]

$E = \left\{(a,b) \mid a \in I \text{ and } b \in R \right\}$ , $P = \left\{(a,b) \mid a \in E \text{ and } b \in R \right\}$ but we cannot solve for the set $E$ because we are missing information.

3 0

2 years ago

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The graph of the parent function f(x) = x2 is dashed and the graph of the transformed function g(x) = (x – h)2 is solid. Use the

STALIN [3.7K]

The graph of the parent function f(x) = x2 is dashed and the graph of the transformed function g(x) = (x – h)2 is solid.

If h=3 the vertex shifts to (3,0).

If h=-5 the vertex is shifted to (-5,0)

I hope this helps! Sorry no one got back to you in the past few days ):

3 0

2 years ago

Read 2 more answers

You and a friend each have a collection of tokens. Initially, for every 8 tokens you had, your friend had 3. After you give half

Sonbull [250]

Answer: 30 token

Step-by-step explanation:

Since, according to the question,

Initially, for every 8 tokens I had, my friend had 3.

Therefore, ratio of tokens that me and my friend is 8 : 3

Let I have 8 x tokens and my friend has 3 x tokens, where x is any number.

Then again according to the question,

After I gave half of your friend, my friend now has 18 more tokens than you.

That is, (3x + 4x) - 4x = 18

⇒ 7x - 4x = 18

⇒ 3x = 18

⇒ x = 6

Therefore , Initially the difference between me and my friend's token = 8 x - 3 x = 5 x = 5 × 6 = 30

6 0

2 years ago

A disadvantage of the contention approach for LANs, such as CSMA/CD, is the capacity wasted due to multiple stations attempting

sammy [17]

Answer:

The overview of the given problem is outlined in the following segment on the explanation.

Step-by-step explanation:

The proportion of slots or positions that have been missed due to numerous concurrent transmission incidents can be estimated as follows:

Checking a probability of transmitting becomes "p".

After considering two or even more attempts, we get

Slot fraction wasted,

= $[1-no \ attempt \ probability-first \ attempt \ probability-second \ attempt \ probability+...]$

On putting the values, we get

= $1-no \ attempt \ probability-[N\times P\times probability \ of \ attempts]$

= $1-(1-P)^{N}-N[P(1-P)^{N}]$

So that the above seems to be the right answer.

8 0

2 years ago