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laiz [17]
2 years ago
12

What is the percent composition by mass of sulfur in the compound MgSO4 (gram-formula mass =120. grams per mole)?(1) 20.% (2) 27

% (3) 46% (4) 53%
Chemistry
1 answer:
TEA [102]2 years ago
8 0
<span>Solving for the percent composition by mass of sulfur. The formula would be: %S = mass of sulfur / mass of compound x 100% Plugging in our data: %S = 32 amu / 120 amu x 100% %S = 0.266666 x 100% %S = 26.66% Rounded off to two significant numbers it will be 27%. Therefore the answer is number 2.</span>
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For the reaction: MgF2(s) ⇌ Mg2+(aq) + 2F- (aq), Ksp= 6.4 × 10-9, the addition of 0.10 M NaF to the solution cause what effect o
galina1969 [7]

Answer:

Shifts the equilibrium to the left. reduces solubility.

Explanation:

  • MgF2(s) ↔ Mg2+(aq) + 2F-(aq)

          S                   S              2S

∴ Ksp = 6.4 E-9 = [ Mg2+ ] * [ F- ]² = S * (2S)²

⇒ 4S² * S = 6.4 E-9

⇒ 4S³ = 6.4 E-9

⇒ S³ = 1.6 E-9

⇒ S = 1.1696 E-3 M

  • NaF(s) → Na+(aq)  +  F-(aq)

        0.10M     0.10M        0.10M

  • MgF2(s) ↔ Mg2+(aq)  + 2F-(aq)

          S'                 S'              2S' + 0.10

⇒ Ksp = 6.4 E-9 = (S')*(2S' + 0.10)²

If we compare the concentration (0.10 M) of the ion with Ksp ( 6.4 E-9 ); thne we can neglect S' as adding:

⇒ 6.4 E-9 = (S')*(0.10)² = 0.01S'

⇒ S' = 6.4 E-7 M

∴ % S' = ( 6.4 E-7 / 0.1 )*100 = 6.4 E-4% <<< 5%, we can make the assumption

We can observe that S >> S' ( 1.1696 E-3 M >> 6.4 E-7 M ), which shows that the solubility  is reduced by the efect of the common ion from the salt, which causes the equilibrium to shift to the left, precipitating part of MgF2(s).

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It is slow due to the concentration of acid is low.
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2 years ago
Lithium chloride forms three hydrates. They are LiCl.H2O, LiCl.2H2O and LiCl.3H2O.
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Answer:

The answer is LiCl.2H2O

Explanation:

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2 years ago
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