If the car in the opposite direction turns the signal on your vehicle, then it is only likely to give way and let him or her turn before you make your turn because he or she is in the right of way and by doing this, it will prevent any complication from happening and to be able to show respect and politeness in driving.
<h3><u>Answer;</u></h3>
33.9 pounds
<h3><u>Explanation</u>;</h3>
In order for the ladder to be in equilibrium, the net torque should be equal to zero. Therefore, the torque in the opposite directions should equal each other:
Clockwise torque = Counter clockwise torque
Torque is the product of the applied force and the distance between that force and the axis of rotation.
Wι (7.5 ft) cos 53° + Wb (6 ft) cos 53° = F (15 ft) sin 53 °
Substitute the values for the weights of the ladder and the boy, respectively.
(20 lb) (7.5 ft)cos 53° + (75 lb) (6 ft) cos 53° = F(15 ft) sin 53°
Solving for F;
F = ((30 ×7.5 × cos 53°) + (75 × 6 × cos 53°))/ (15 × sin 53°)
= 33.9 lb
<u>= 33.9 Pounds</u>
<span>v =Integral(F/m)dtv=Integral(F/m)dt
=â«50(6t2â’4t+3)/5dt=â«05(6t2â’4t+3)/5dt
=1/5â—(2t3â’2t2+3t)|(0,5)=1/5â—(2t3â’2t2+3t)|(0,5)
=1/5â—(250â’50+15)=1/5â—(250â’50+15)
=215/5=215/5
=43m/s.</span>