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Sergeu [11.5K]
2 years ago
15

How many of the elements in the second row of the periodic table (li through ne) will have at least one unpaired electron in the

ir electron configurations?
Chemistry
1 answer:
nexus9112 [7]2 years ago
4 0
The second row of the periodic table consists of the elements:
Lithium (3)
Beryllium (4)
Boron (5)
Carbon (6)
Nitrogen (7)
Oxygen (8)
Fluorine (9)
Neon (10)

The number in the bracket shows the atomic number of the elements, which also indicates the number of electrons they have. We see that the odd numbered elements, Li, B, N and F will all have unpaired electrons. Therefore, 4 elements will have unpaired electrons in their electronic configuration.
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Using the idea of electronegativity difference for predicting polarity of bonds and considering the shape of the following molec
Zinaida [17]
See electronegativity is the tendency of an atom to gain an electron and flourine with a valecy of one and a vey small size is the most electronegetive because its orbitals are quite closed to the nucleus and hence the attraction is quite strong so it can attract an electron.the question that arises is that some smaller atoms should be more electronegetive as they are closer to the nucleus but it need more energy for them as compared to flourine to complete their octet. now polarity increases when two atoms of quite different sizes form a compound ... the more electronegetive atom will always attract the bond pair forming a negetive charge on it and positive on the less electroneg. one and polarity increases with electronegetivity of the anion.now as your question says 
<span>5=I2.. because both the atoms are same there wont be permanent polarity </span>
<span>4=HI iodine is the least electronegetive of all the halogens due to its large size,electronegetivity decreases down the group </span>
<span>3=HBr bromine is the 2nd largest halogen </span>
<span>2=HCl chlorine is the 3rd largest halogen </span>
<span>1=HF fluorine is the smallest halogen making and hence makes the most polar</span>
8 0
2 years ago
Salt in crude oil must be removed before the oil undergoes processing in a refinery. The
irina1246 [14]

Answer:

\large \boxed{0.64 \, \%}

Explanation:

Assume you are using 1 L of water.

Then you are washing 4 L of salty oil.

1. Calculate the mass of the salty oil

Assume the oil has a density of 0.86 g/mL.

\text{Mass of oil} = \text{4000 mL} \times \dfrac{\text{0.86 g}}{\text{1 mL}} = \text{3440 g}

2. Calculate the mass of salt in the salty oil

\text{Mass of salt} = \text{3440 g} \times \dfrac{\text{5 g salt}}{\text{100 g oil}} = \text{172 g salt}

3. Calculate the mass of salt in the spent water

\text{Mass of salt} = \text{1000 g water} \times \dfrac{\text{15 g salt}}{\text{100 g water}} = \text{150 g salt}

4. Mass of salt remaining in washed oil

Mass = 172 g - 150 g = 22 g  

5. Concentration of salt in washed oil

\text{Concentration} = \dfrac{\text{22 g}}{\text{3440 g}} \times 100 \, \% = \mathbf{0.64 \, \%}\\\\\text{The concentration of salt in the washed oil is $\large \boxed{\mathbf{0.64 \, \%}}$}

3 0
2 years ago
What mass of powdered drink mix is needed to make a 0.5 M solution of 100 mL?
Maru [420]

Answer:

There is 17,114825 g of powdered drink mix needed

Explanation:

<u>Step 1 :</u> Calculate moles

As given, the concentration of the drink is 0.5 M, this means 0.5 mol / L

Since the volume is 100mL, we have to convert the concentration,

⇒0.5 / 1   =  x /0.1    ⇒ 0.5* 0.1  = x = 0.05 M

This means there is 0.05 mol per 100mL

e

<u>Step 2 </u>: calculate mass of the powdered drink

here we use the formula n (mole) = m(mass) / M (Molar mass)

⇒ since powdered drink mix is usually made of sucrose (C12H22O11) and has a molar mass of 342.2965 g/mol.

0.05 mol = mass / 342.2965 g/mol

To find the mass, we isolate it ⇒0.05 mol * 342.2965 g/mol = 17,114825g

There is 17,114825 g of powdered drink mix needed

3 0
2 years ago
Read 2 more answers
A mass of 5.4 grams of aluminum (al) reacts with an excess of copper (ii) chloride (cucl2) in solution, as shown below. 3cucl2 2
horrorfan [7]

Answer:

Mass of copper produced is 19.07g

Explanation:

Let's bring out the chemical equation;

3CuCl2 + 2Al → 2AlCl3 + 3Cu

3           :   2       :   2       : 3

Upon confirming that the reaction is indeed balanced, we can proceed.

The questions asks to calculate mass of Cu formed when a mass of 5.4g of Al is being used.

From the equation, what is the relationship between Al and Cu?

2 mol of Al would react to form 3 mol of Cu

Expressing this in terms of mass, we have;

mass = no. of moles * molar mass

Mass of Aluminium = 2 * 26.98 = 53.98 g

Mass of Copper = 3 * 63.546 = 190.638g

This means;

53.98 g of Al would react to form 190.638g of Cu

So how much Cu would form from 5.4 g of Al?

This leads us to;

53.98 = 190.638

5.4 = x

Upon cross multiplication, we are left with;

x = (190.638 * 5.4) / 53.98

x = 19.07 g

Mass of copper produced is 19.07g

8 0
2 years ago
Jesse travels 3.0 meters east and then turns and travels 4.0 meters north. The trip requires 35 seconds. What is his velocity? 0
melisa1 [442]
Displacement = √(3² + 4²)
Displacement = 5 meters north east

Velocity = displacement / time
Velocity = 5 / 35
Velocity = 0.14 m/s northeast
6 0
2 years ago
Read 2 more answers
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