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2 years ago

find a model for simple harmonic motion if the position at t=0 is 0 the amplitude is 5 centimeters and the period is 4 seconds

Mathematics

2 answers:

Alexeev081 [22]2 years ago

7 0

Answer:

y = 5sin $(\frac{x}{2})$

Step-by-step explanation:

Since harmonic motion is represented by the sine wave equation.

y = a sin (bx)

where a = amplitude

period = $\frac{2\pi}{b}$

Amplitude of the harmonic motion is given as 5 and period is 4 seconds.

so a = 5

and 4 = $\frac{2\pi}{b}$ ⇒ b = $\frac{2\pi}{4}$

b = $\frac{\pi}{2}$

Now we replace the values of a and b in the sine equation

y = 5sin $(\frac{x}{2})$

Jobisdone [24]2 years ago

6 0

<span>d = 5sin(πt)
hope this helped</span>

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Dafna11 [192]

Hey there!

Let's write this as a ratio/proportion.

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2 years ago

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Montano1993 [528]

Answer:

First option: $y=(x + 8)(x + 3)$

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Given the quadratic equation $y = x^2 + 11x + 24$ , you need to factor it.

To do this, you need to find two number that when you add them you get 11 and when you multply them you get 24. These numbers are: 8 and 3.

Therefore, knowing this, you can factor the quadratic equation:

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2 years ago

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natali 33 [55]

Answer:

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guapka [62]

Answer:

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