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worty [1.4K]
2 years ago
4

Chemistry balance skeleton reaction? Balance the following skeleton reactions and identify the oxidizing and reducing agents.; i

nclude states-of-matter please! 1.BH4‾(aq) + ClO3‾(aq) → H2BO3‾(aq) + Cl ‾(aq) [basic] 2.CrO42-(aq) + N2O(g) → Cr3+(aq) + NO(g) [acidic]
Chemistry
1 answer:
guajiro [1.7K]2 years ago
3 0
The correct balanced redox reactions would be as follows:

<span>1.BH4‾(aq) + ClO3‾(aq) → H2BO3‾(aq) + Cl ‾(aq) [basic]
</span>By using the half-reaction method, we will obtain the following: 
<span>BH4-(aq) + 8 OH- = H2BO3- + 5H2O + 8 e- </span>
<span>ClO3- + 3H2O + 6 e- = Cl- + 6OH- 
</span>
<span>The LCM for the 2 half-reactions would be 24. We add these reactions as follows: </span>

<span>3 BH4- + 24 OH- = 3H2BO3- + 15 H2O + 24e- </span>
<span>4 ClO3- + 12 H2O + 24e- = 4Cl- + 24OH-
</span>-----------------------------------------------------------------
<span>3 BH4- + 4ClO3- = 3H2BO3- + 4Cl- + 3H2O </span><span>


2.CrO42-(aq) + N2O(g) → Cr3+(aq) + NO(g) [acidic]
By the same procedure above, 

</span>(CrO4)2- + 8 H+ + 3 e- = Cr3+ + 4 H2O 
<span>N2O + H2O = 2 NO + 2 H+ + 2 e- </span>
<span>
The LCM would be 6. </span>

<span>2 (CrO4)2- + 16 H+ + 6 e- = 3 Cr3+ + 8 H2O</span>
<span>3 N2O(g) + 3 H2O(l) = 6 NO(g) + 6 H+ + 6 e- </span>
<span>----------------------------------------------------------------------------------
</span><span>2 (CrO4)2- + 3 N2O + 10 H+ = 3 Cr3+ + 6 NO + 5 H2O</span>
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