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marishachu [46]
2 years ago
5

why is it less effective to wash an insoluble precipitate with 15 ml of water once than it is to wash the precipitate with 3 ml

of water 5 times ?
Chemistry
1 answer:
MArishka [77]2 years ago
6 0

It is less effective to wash an insoluble precipitate with 15 ml of water once than it is to wash the precipitate with 3 ml of water 5 times because commonly, when you clean an <span>indissoluble precipitate with water, the water will not be completely saturated with contaminates. Therefore, the absorption of the contaminates would lower with each wash, since if you only washed it once with a bigger amount or volume of water, it’d become less contaminated with the wash water but it wouldn’t get rinsed numerous times.</span>

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For which of the following properties does sodium have a larger value than rubidium? Select all that apply.
Doss [256]

Answer:

Ionization energy

Electronegativity

Explanation:

-due to its smaller ionic radius....the electron in the outter most shell tends to expierence a stronger nuclear attraction...which makes it harder to remove the electron from the sodium atom

-Rubidium has lesser ionization energy because its (i) affected by its larger ionic radius which tends to lessen the nuclear attraction ...hence making it easier to remove the electron...(ii)and also by the screening effect done by the inner shells, which also tends to lessen the nuclear attraction.

Sodium has a higher electronegativity than rubidium;

Electronegativity is the charge density of electrons in an atom...in which its high when the atomic radius is smaller...

So hence due to the sodium atomic radius being smaller...it tends to have a higher charge density than rubidium....which then gives it a higher electronegativity value

4 0
2 years ago
84. Heavy water, D2O (molar mass = 20.03 g mol–1), can be separated from ordinary water, H2O (molar mass = 18.01), as a result o
ipn [44]

Answer:

relative rate of diffusion is 1.05

Explanation:

According to Graham's law of difussion:

Rate of diffusion is inversely proportional to the square root of molecular weight of a molecule.

For two given molecules:

\frac{(rate)_{1}}{(rate)_{2}}=\frac{\sqrt{M_{2}} }{\sqrt{M_{1}}}

The given molecules are

Water = 18.01

Heavy water =20.03

Thus the relative rate of diffusion will be:

\frac{(rate)_{water}}{(rate)_{heavywater}}=\sqrt{ \frac{20.03}{18.01}}=1.05

8 0
2 years ago
Formulating an Investigative Question In this experiment, you will use a track and a toy car to explore the concept of movement.
Solnce55 [7]

Answer:

A scientific question to be asked is; <em>What is the average speed of the toy car?</em>

Explanation:

A scientific question is a question which is well defined, the values in the question can be measured, and the inputs and outputs related to the question are controllable

The parameters measured in the experiment are;

The time elapsed during the movement of the car, <em>Δt</em>

The distance the car moves, <em>d</em>

From the obtained measurements, the value can be calculated is the average speed of the toy car as follows;

The \ average \ speed \ of \ the \ toy \ car, \ v_{avg} = \dfrac{d}{\Delta t}

Therefore, a scientific question to be asked that will be answered by doing the experiment is; What is the average speed of the toy car?

3 0
2 years ago
A sample of ammonia has a mass of 82.9 g. how many molecules are in this sample?
alina1380 [7]
The chemical formula for ammonia is NH3. So first, you need to find the molar mass of ammonia (how many grams in one mole).
N=14g
H3=3g
So one mole of NH3 is 17 grams, you can divide 82.9 grams by 17 grams to find the number of molecules. The answer should be 4.876 moles (molecules) of ammonia. Hope this helps!
8 0
2 years ago
Read 2 more answers
A 0.15 m solution of chloroacetic acid has a ph of 1.86. What is the value of ka for this acid?
dem82 [27]

Answer: 1.67\times 10^{-3}

Explanation:

ClCH_2COOH\rightarrow ClCH_2COO^-+H^+

   cM              0             0

c-c\alpha        c\alpha          c\alpha  

So dissociation constant will be:

K_a=\frac{(c\alpha)^{2}}{c-c\alpha}

Given:  c = 0.15 M

pH = 1.86

K_a = ?

Putting in the values we get:

Also pH=-log[H^+]

1.86=-log[H^+]

[H^+]=0.01

[H^+]=c\times \alpha

0.01=0.15\times \alpha

\alpha=0.06

As [H^+]=[ClCH_2COO^-]=0.01

K_a=\frac{(0.01)^2}{(0.15-0.15\times 0.06)}

K_a=1.67\times 10^{-3]

Thus the vale of K_a for the acid is 1.67\times 10^{-3}

4 0
2 years ago
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