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2 years ago

"if the price of mints was raised from 5 cents each to 15 cents for two, what was the increase in price per mint?"

2 answers:

7 0

15 cents for two mints gives 7.5 cents for one mint
7.5 cents is an increase of 2.5 cents from the previous price 5 cents for one mint and it is a 50% increase

eimsori [14]2 years ago

6 0

Answer:

Increase in price per mint is 2.5 cents .

Step-by-step explanation:

The price of mints is raised from 5 cents each to 15 cents for two.15 cents is the rice in price for two mints .Hence rise in price for each mint is 15÷2=7.2 cents.

Rise in price for each mint = 7.2-5=2.5cents.

Percent increase = $\frac{2.5}{5} (100)=50$

There is 50% increase in price per mint.

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6. Charlie can spend up to $8 on lunch. He wants to buy a tuna sandwich, a bottle of

PilotLPTM [1.2K]

Answer:

The maximum number of pounds of potato salad that Charlie can buy is 0.375

Step-by-step explanation:

see the attached figure to better understand the problem

Let

a ----> the cost of one tuna sandwich

b ----> the cost of a bottle of apple juice

c ----> the cost per pound of potato salad

x ----> pounds of potato salad

we have

$a=\$4.25$

$b=\$2.25$

$c=\$4.00/lb$

we know that

He wants to buy a tuna sandwich, a bottle of apple juice, and x pounds of potato salad and can spend up to $8

The inequality that represent this situation is

$a+b+cx \leq 8$

substitute the given values

$4.25+2.25+4.00x \leq 8$

Solve for x

Combine like terms

$6.50+4.00x \leq 8$

Subtract 6.50 both sides

$4.00x \leq 8-6.50$

$4.00x \leq 1.50$

Divide by 4 both sides

$x \leq 1.50/4.00$

$x \leq 0.375\ lbs$

therefore

The maximum number of pounds of potato salad that Charlie can buy is 0.375

3 0

2 years ago

Set R contains all integers from 10 to 125, inclusive, and Set T contains all integers from 82 to 174, inclusive. How many integ

SCORPION-xisa [38]

Answer: PLEASE GIVE BRAINLIEST

72 integers

Step-by-step explanation:

Starting From 82-174 every integer is included in T so every integer that is not included in T but included in R would be 82-10 so every integer from 10 to 82.

3 0

2 years ago

How many 5-digit numbers are there that are divisible by either 45 or 60 but are not divisible by 90?

o-na [289]

Answer:

2500 numbers

Step-by-step explanation:

Problem;

Solving for the number of 5-digit numbers divisible either by 45 or 60 but not divisible by 90;

Let us approach this in a step wise manner;

5 -digits numbers ranges from 10,000 to 99,999

To solve this problem, let us find the number of digits that are divisible by 45;

the first number divisible by 45 within this range is 10035

the last number divisible by 45 in this range is 99990

increment is 45

The total number in this range is:

$\frac{last number - first number}{increment}$ + 1 = $\frac{99990 - 10035}{45}$ + 1

= 2000 numbers

To solve this problem, let us find the number of digits that are divisible by 60;

the first number divisible by 60 within this range is 10020

the last number divisible by in this range is 99960

increment is 60

$\frac{99990 - 10080 }{90}$

The total number in this range is:

$\frac{last number - first number}{increment}$ + 1 = $\frac{99960 - 10020}{60}$ + 1

= 1500 numbers

To solve this problem, let us find the number of digits that are divisible by 90;

the first number divisible by 90 within this range is 10080

the last number divisible by in this range is 99990

increment is 90

The total number in this range is:

$\frac{last number - first number}{increment}$ + 1 = $\frac{99990 - 10080}{90}$ + 1

= 1000 numbers

Now solution:

Number of 5 digits = number of 45 + number of 60 - number of 90

= 2000 + 1500 - 1000

= 2500 numbers

3 0

2 years ago

Michael is shipping his mother's birthday gift to her in a rectangular box. If the gift's dimensions are 2 inches long by 5 inch

stepan [7]

Answer:

112

Step-by-step explanation:

4 0

2 years ago

Suppose you are an expert on the fashion industry and wish to gather information to compare the amount earned per month by model

Ann [662]

Answer:

(1) The degrees of freedom for unequal variance test is (14, 11).

(2) The decision rule for the 0.01 significance level is;

If the value of our test statistics is less than the critical values of F at 0.01 level of significance, then we have insufficient evidence to reject our null hypothesis.

If the value of our test statistics is more than the critical values of F at 0.01 level of significance, then we have sufficient evidence to reject our null hypothesis.

(3) The value of the test statistic is 0.3796.

Step-by-step explanation:

We are given that you are an expert on the fashion industry and wish to gather information to compare the amount earned per month by models featuring Liz Claiborne's attire with those of Calvin Klein.

The following is the amount ($000) earned per month by a sample of 15 Claiborne models;

$3.5, $5.1, $5.2, $3.6, $5.0, $3.4, $5.3, $6.5, $4.8, $6.3, $5.8, $4.5, $6.3, $4.9, $4.2 .

The following is the amount ($000) earned by a sample of 12 Klein models;

$4.1, $2.5, $1.2, $3.5, $5.1, $2.3, $6.1, $1.2, $1.5, $1.3, $1.8, $2.1.

(1) As we know that for the unequal variance test, we use F-test. The degrees of freedom for the F-test is given by;

$\text{F}_(_n__1-1, n_2-1_)$

Here, $n_1$ = sample of 15 Claiborne models

$n_2$ = sample of 12 Klein models

So, the degrees of freedom = ( $n_1-1, n_2-1$ ) = (15 - 1, 12 - 1) = (14, 11)

(2) The decision rule for 0.01 significance level is given by;

If the value of our test statistics is less than the critical values of F at 0.01 level of significance, then we have insufficient evidence to reject our null hypothesis.

If the value of our test statistics is more than the critical values of F at 0.01 level of significance, then we have sufficient evidence to reject our null hypothesis.

(3) The test statistics that will be used here is F-test which is given by;

T.S. = $\frac{s_1^{2} }{s_2^{2} } \times \frac{\sigma_2^{2} }{\sigma_1^{2} }$ ~ $\text{F}_(_n__1-1, n_2-1_)$

where, $s_1^{2}$ = sample variance of the Claiborne models data = $\frac{\sum (X_i-\bar X)^{2} }{n_1-1}$ = 1.007

$s_2^{2}$ = sample variance of the Klein models data = $\frac{\sum (X_i-\bar X)^{2} }{n_2-1}$ = 2.653

So, the test statistics = $\frac{1.007}{2.653 } \times 1$ ~ $\text{F}_(_1_4,_1_1_)$

= 0.3796

Hence, the value of the test statistic is 0.3796.

3 0

2 years ago