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2 years ago

9

a game spinner has regions that are numbered 1 through 8. if the spinner is used twice, what is the probability that the first n

umber is a 3 and the second is a 7?

2 answers:

tester [92]2 years ago

8 0

These are both independent events because 1 spin does not effect the other.

P(1st spin is 3) = 1/8
P(2nd spin is 7) = 1/8

P(both) = 1/8 * 1/8 = 1/64

SashulF [63]2 years ago

4 0

Each number on the spinner has an equally likely chance of being selected, 1/8. For this type of problem you multiply the probabilities.
P(3) = 1/8
P(7) = 1/8
(1/8) * (1/8) = 1/64

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