Answer:
k = ![\frac{[HOCl]^2}{[Cl]^2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BHOCl%5D%5E2%7D%7B%5BCl%5D%5E2%7D)
Explanation:
The equilibrium-constant expression is defined as the ratio of the concentration of products over concentration of reactants. Each concentration is raised to the power of their coefficient.
Also, pure solid and liquids are not included in the equilibrium-constant expression because they don't affect the concentration of chemicals in the equilibrium
The global reaction is:
2 HgO (s) + H₂O (l) +2 Cl₂ (g) ⇌ 2 HOCl (aq) + HgO⋅HgCl₂ (s)
Thus, equilibrium-constant expression is:
<em>k = </em>
You don't include HgO nor HgO⋅HgCl₂ because are pure solids nor water because is pure liquid.
I hope it helps!
Answer:
2450 cm3
Explanation:
Volume of cylinder = V=πr2h
2.45L = 2450mL
1mL = 1 cm cubed
2450mL = 2450 cm cubed
Answer:
Molecular formula = C₆H₁₂O₆
Explanation:
Given data:
Mass of hydrogen = 31.7 g
Mass of carbon = 283.4 g
Mass of oxygen = 377.4 g
Molar mass of compound = 176.124 g/mol
Molecular formula = ?
Solution:
Number of gram atoms of H = 31.7 / 1.01 = 31.4
Number of gram atoms of O = 377.4 / 16 = 23.6
Number of gram atoms of C = 283.4 / 12 = 23.6
Atomic ratio:
C : H : O
23.6/23.6 : 31.4/23.6 : 23.6/23.6
1 : 1.33 : 1
C : H : O =3 (1 : 1.33 : 1
)
Empirical formula is C₃H₄O₃.
Molecular formula:
Molecular formula = n (empirical formula)
n = molar mass of compound / empirical formula mass
Empirical formula mass = 3×12+4+3×16 = 88
n = 176.124 / 88
n = 12
Molecular formula = n (empirical formula)
Molecular formula = 2 (C₃H₄O₃)
Molecular formula = C₆H₁₂O₆
Displacement = √(3² + 4²)
Displacement = 5 meters north east
Velocity = displacement / time
Velocity = 5 / 35
Velocity = 0.14 m/s northeast
Answer:
c = 4016.64 j/g.°C
Explanation:
Given data:
Mass of substance = 2.50 g
Calories release = 12 cal (12 ×4184 = 50208 j)
Initial temperature = 25°C
Final temperature = 20°C
Specific heat of substance = ?
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
Solution:
Q = m.c. ΔT
ΔT = T2 - T1
ΔT = 20°C - 25°C
ΔT = -5°C
50208 j = 2.50 g . c. -5°C
50208 j = -12.5 g.°C .c
50208 j /-12.5 g.°C = c
c = 4016.64 j/g.°C
