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abruzzese [7]
2 years ago
6

I make my cup of coffee in the morning by pouring boiling water over ground-up coffee beans held in a special piece of paper and

by collecting the brown liquid that comes through. which techniques of the five described in the background section is used in the preparation of the drink?
Chemistry
1 answer:
Zigmanuir [339]2 years ago
4 0
Since there are no choices given, my answer might not be what you're looking for. But it can definitely be a correct answer. The technique is called filtration. Filtration is a physical separation to separate the liquid and solid in a mixture. The mixture should be composed of an insoluble solid in a solvent. The mixture is usually passed through a semi-permeable barrier. In this case, a special piece of paper is used. The solvent is the liquid and the solid is the coffee bean grounds. Only the liquid can pass through the paper. The liquid that passes through the paper is generally called a filtrate.
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Vilka [71]

Answer:

58.61 grams

Explanation:

Taking The molecular weight of NaCl = 58.44 grams/mole

<u>Determine how many grams of NaCl to prepare the bath solution </u>

first we will calculate the moles of NaCl that is contained in 6L of 170 mM of NaCI solution

= ( 6 * 170 ) / 1000

= 1020 / 1000 = 1.020 moles

next

determine how many grams of NaCl

= moles of NaCl * molar mass of NaCl

= 1.020 * 58.44

= 58.61 grams

4 0
2 years ago
Write down the dissolution equation for rubidium chromate dissolving in water. (Chromate is a polyatomic ion with the formula Cr
ycow [4]

Answer:

Four moles of the cation

Explanation:

2Rb2CrO4(s)<--------> 4Rb^+(aq) + 2CrO4^2-(aq)

Now looking at the reaction equation, it can be seen that one mole of rubidium chromate contains two moles of rubidium ions and one mole of chromate ions.

The dissolution of two moles of rubidium chromate should then yield four moles of rubidium ions and two moles of chromate ions since the ratio of ions present is 2:1.

This explains the reaction equation written above for the dissolution of two moles of rubidium chromate as shown.

5 0
2 years ago
How much heat is absorbed/released when 25.00 g of NH3(g) reacts in the presence of excess O2(g) to produce NO(g) and H2O(l) acc
Novay_Z [31]

Answer:

429.4 kJ are absorbed in the endothermic reaction.

Explanation:

The balanced chemical equation tells us that 1168 kJ of heat are absorbed in the reaction when 4 mol of NH₃ (g) react with 5 mol O₂ (g).

So what we need is to calculates how many moles represent 25 g NH₃(g) and calculate the heat absorbed. (NH₃ is the limiting reagent)

Molar Mass NH₃  = 17.03 g/mol

mol NH₃ = 25.00 g/ 17.03 g/mol = 1.47 mol

1168 kJ /4 mol NH₃  x 1.47 mol  NH₃ =  429.4 kJ

6 0
2 years ago
How many atoms are centered on the (100) plane for the fcc crystal structure?
Setler [38]

Here, we have to get the number of atoms present in the 100 plane of the FCC crystal lattice.

There will be 2 atoms in 100 plane of FCC crystal lattice.

In the face centered crystal (FCC) lattice there are atoms at each corner of the cube and each are shared by 4 another atoms. And an atom is present at the face of the crystal.

For the 100 plane of the Miller indices the intercepts are a, ∞, ∞ or 2a, ∞, ∞.

Thus, for the 4 atoms of the corner at the cube shared by 4 other atoms will contribute, 4 × \frac{1}{4} = 1 and the un-shared atoms at the face will contribute another 1, which make the total atom 1 + 1 = 2.

5 0
2 years ago
Consider the reaction below. 2Al2O3 4Al + 3O2 How many moles of oxygen are produced when 26.5 mol of aluminum oxide are decompos
Aloiza [94]

 The moles  of  oxygen  that are produced when 26.5 mol  of Al2O3  decomposes  is  39.8 mol


<u>calculation</u>

<u> </u> 2Al2O3  + 4Al +3 O2


  •  use the mole  ratio  of Al2O3  to O2  to determine the moles of  O2.
  • that is   from  the  equation above the mole ratio of Al2O3 : O2 is 2:3  
  • the moles of O2  is therefore=n 26.5 mol  x3/2= 39.8  moles
3 0
2 years ago
Read 2 more answers
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