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adelina 88 [10]
2 years ago
3

A jogger travels due south and in the process his displacement vector has a magnitude of 4.68 km. he then jogs due west what is

the magnitude of the displacement vector in the due west direction if the magnitude of the total displacement vector is 7.41 km
Physics
1 answer:
ValentinkaMS [17]2 years ago
6 0

In this case, we can draw a right triangle. We are given the measure of one of the sides and the hypotenuse. Therefore we can calculate for the magnitude of the west direction using the hypotenuse formula. Let us say that b = west distance:

7.41^2 = b^2 + 4.68^2

b^2 = 33.0057 km^2

b = 5.75 km

 

<span>Hence the magnitude in the west direction is about 5.75 km</span>

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Two small diameter, 10gm dielectric balls can slide freely on a vertical channel each carry a negative charge of 1microcoulomb.
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Answer:

The distance of separation is d = 0.092 \ m

Explanation:

The mass of the each ball is  m= 10 g  =  0.01 \ kg

 The negative charge on each ball is q_1 =q_2=q =  1 \mu C  =  1 *10^{-6} \ C

Now we are told that the lower ball is  restrained from moving this implies that the net force acting on it is  zero

Hence the gravitational force acting on the lower ball is equivalent to the electrostatic force i.e

          F =  \frac{kq_1 * q_2}{d}

=>       m* g  =  \frac{kq_1 * q_2}{d}

here k the the coulomb's  constant with a value  k = 9*10^{9} \ kg\cdot m^3\cdot s^{-4}\cdot A^2.

So  

      0.01 * 9.8  =  \frac{ 9*10^9 *[1*10^{-6} * 1*10^{-6}]}{d}

            d = 0.092 \ m

5 0
2 years ago
Argon in the amount of 1.5 kg fills a 0.04-m3 piston cylinder device at 550 kPa. The piston is now moved by changing the weights
Arlecino [84]

Answer:

               275 kPa

Explanation:

             mass of the gas=m=1.5 kg

             initial volume if the gas=V₁=0.04 m³

             initial pressure of the gas= P₁=550 kPa

as the condition is given final volume is double the initial volume

             V₂=final volume

             V₂=2 V₁

As the temperature is constant

             T₁=T₂=T

\frac{P1V1}{T1}=\frac{P2 V2}{T2}

putting the values in the equation.

\frac{P1V1}{T1}=\frac{P2 *2V1}{T2}

P₂=\frac{P1}{2}

P₂=\frac{550}{2}

P₂=275 kPa

So the final pressure of the gas is 275 kPa.

           

3 0
2 years ago
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Answer: Neither Sandra nor Marissa will be in her THR zone.


Explanation:


1) Actual pulse of both Sandra and Marissa : 144 bpm


2) Decrease of 20 bpm ⇒ 144 bpm - 20 bpm = 124 bpm


3) Sandra's TRH is in the range 135 - 172 bpm.


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4) Marissa's TRH range is 143 - 176 bpm.


Since, 124 < 143, she is below the range


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