Answer:
P(t) = 1000e^(0.01155)t
Step-by-step explanation:
Let the population of barangay be expressed according to the exponential formula;
P(t) = P0e^kt
P(t) is the population of the country after t years
P0 is the initial population
t is the time
If barangay has 1000 initially, this means that P0 = 1000
If the population doubles after 60years then;
at t = 60, P(t) = 2P0
Substitute into the formula
2P0 = P0e^k(60)
2 = e^60k
Apply ln to both sides
ln2 = lne^60k
ln2 = 60k
k = ln2/60
k = 0.01155
Substitute k = 0.01155 and P0 into the expression
P(t) = 1000e^(0.01155)t
Hence an exponential model for barangay's population is
P(t) = 1000e^(0.01155)t
Answer:
$4200
Step-by-step explanation:
12% of 35000, because it's between 9,526 and 38,700.
That is .12 * 35000 = $4200
Answer:
Step-by-step explanation:
After one year
A=p(1+r/n)^nt
=2000(1+0.03/12)^12*1
=2000(1+0.0025)^12
=2000(1.0025)^12
=2000(1.0304)
=$2060.8
After two-years
A=p(1+r/n)^nt
=2060.8(1+0.03/12)^12*2
=2060.8(1+0.0025)^24
=2060.8(1.0025)^24
=2060.8(1.0618)
=$2188.157
After three years
A=p(1+r/n)^nt
=2188.157(1+0.03/12)^12*3
=2188.157(1+0.0025)^36
=2188.157(1.0025)^36
=2188.157(1.0941)
=$2394.063
Answer:
The car gets 30 miles to the gallon
After the car has traveled 80 miles, gallons of gas have been consumed.
Step-by-step explanation:
