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cupoosta [38]
2 years ago
14

Employee C is paid an hourly rate of $13.25 per hour and works 2,080 hours per year. The employee was just promoted and received

a 15% raise. What is the employee's new yearly salary?
Mathematics
2 answers:
svetlana [45]2 years ago
8 0

Answer:

$31,694

Step-by-step explanation:

Working 2080 hours at $13.25 per hour means the employee earns

13.25(2080) = $27560 per year.

After the employee receives a 15% raise, this will mean 100+15 = 115% of the current salary.  115% = 115/100 = 1.15; this gives us

1.15(27560) = 31694 per year

Ostrovityanka [42]2 years ago
4 0
He made 13.25 per hr.....and just received a 15% raise...
13.25 + 0.15(13.25) = 13.25 + 1.99 = 15.24 per hr (with the raise)

15.24 per hr for 2080 hrs = 
15.24 * 2080 = 31699.20 <==
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Consider f(x) = 1.8x – 10 and g(x) = −4. A 2 column table with 6 rows. The first column, x, has the entries, negative 4, 0, 2, 4
viktelen [127]

Answer:1.8x – 10 = –4; x = 1.8 x minus 10 equals negative 4; x equals StartFraction 10 Over 2 EndFraction.

1.8 - 10= -4 x= -10/9

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Tan 235° = 2tan20°+ tan215°​
Mariulka [41]

Given :  tan 235 = 2 tan 20 + tan 215

To Find : prove that

Solution:

tan 235 = 2 tan 20 + tan 215

Tan x = Tan (180 + x)

tan 235 = tan ( 180 + 55) = tan55

tan 215 = tan (180 + 35) = tan 35

=> tan 55 = 2tan 20 + tan 35

55 = 20 + 35

=> 20  = 55 - 35

taking Tan both sides

=> Tan 20 = Tan ( 55 - 35)

=> Tan 20  = (Tan55 - Tan35) /(1 + Tan55 . Tan35)

Tan35 = Cot55 = 1/tan55 => Tan55 . Tan35 =1

=> Tan 20  = (Tan 55 - Tan 35) /(1 + 1)

=> Tan 20  = (Tan 55 - Tan 35) /2

=> 2 Tan 20  = Tan 55 - Tan 35

=> 2 Tan 20 +  Tan 35 = Tan 55

=>  tan 55 = 2tan 20 + tan 35

=>  tan 235 = 2tan 20 + tan 215

QED

Hence Proved

5 0
1 year ago
Match the following guess solutions ypyp for the method of undetermined coefficients with the second-order nonhomogeneous linear
Sunny_sXe [5.5K]

Answer:

Step-by-step explanation:

1 ) Given that

(d^2y/dx^2) + 4y = x - x^2 + 20\\\\ (d^2y/dx^2) + 4y =  - x^2 + x + 20

For a non homogeneous part - x^2 + x + 20 , we assume the particular solution is

y_p(x) = Ax^2 + Bx + C

2 ) Given that

d^2y/dx^2 + 6dy/dx + 8y = e^{2x}

For a non homogeneous part   e^{2x} , we assume the particular solution is

y_p(x) = Ae^{2x}

3 ) Given that

y′′ + 4y′ + 20y = −3sin(2x)

For a non homogeneous part −3sin(2x) , we assume the particular solution is

y_p(x) =  Acos(2x)+Bsin(2x)

4 ) Given that

y′′ − 2y′ − 15y = 3xcos(2x)

For a non homogeneous part  3xcos(2x)  , we assume the particular solution is

y_p(x) = (Ax+B)cos2x+(Cx+D)sin2x

4 0
1 year ago
The density of air is approximately 1.225 kg/m^3 what is the volume of a soccer ball if the mass of the air it contains is 0.08
svetoff [14.1K]
Using the the density(D)-mass(m)-volume(V) formula m=DV, we can calculate the volume  V= \frac{m}{D}= \frac{0.08}{1.225}= 0.0653 m^{3} 
8 0
1 year ago
Which equation is the inverse of y = 2x2 – 8?
Marrrta [24]

The inverse of the the function above is y = \sqrt{\frac{x+8}{2}}


In order to find the inverse of any function, you need to switch the x and y values. Once you've done that, you need to solve for the new y value. The resulting equation will be your inverse. The work for this one is below.


y = 2x^2 - 8 ----> Switch the terms

x = 2y^2 - 8 ----> Add 8 to both sides.

x + 8 = 2y^2 ----> Divide both sides by 2.

\frac{x+8}{2} = y^2 ----> Now take the square root of both sides.

\sqrt{\frac{x+8}{2}} = y


What's left is your inverse. You can change the order so that it is in a more acceptable form.


y = \sqrt{\frac{x+8}{2}}

6 0
2 years ago
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