If GH has endpoints G(-8, 1) and H(4, 5), then the midpoint M of GH lies on the line y=-x+1
2 answers:
Answer:
Step-by-step explanation:
If GH has a midpoint M(x, y) then we have to determine whether midpoint M lies on the given line y = -x + 1
Since coordinates of G and H are (-8, 1) and (4, 5) so coordinates of the midpoint M will be
x = = -2
and y coordinates of point M will be
y = = 3
Therefore point M is (-2, 3).
Now we plug in the values of x and y in the given equation.
3 = -(-2) + 1
3 = 3
Hence it is proved that the midpoint M of segment GH will lie on the line y = -x + 1
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Answer:
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Step-by-step explanation:
Let
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y ---> the length of the larger cube
we know that
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where
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we have
----> equation A
The volume of the smaller cube is 216 cm^3
so
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solve for x
<em>Find the value of y</em>
<em>Find the volume of the larger cube</em>
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First of all, a bit of theory: since the area of a square is given by
where s is the length of the square. So, if we invert this function we have
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Moreover, the diagonal of a square cuts the square in two isosceles right triangles, whose legs are the sides, so the diagonal is the hypothenuse and it can be found by
So, the diagonal is the side length, multiplied by the square root of 2.
With that being said, your function could be something like this:
double diagonalFromArea(double area) {
double side = Math.sqrt(area);
double diagonal = side * Math.sqrt(2);
return diagonal;
}