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natta225 [31]
2 years ago
15

A gram of gasoline produces 45.0kj of energy when burned. gasoline has a density of 0.77/gml . how would you calculate the amoun

t of energy produced by burning 46.l of gasoline? set the math up. but don't do any of it. just leave your answer as a math expression. also, be sure your answer includes all the correct unit symbols.
Mathematics
1 answer:
jolli1 [7]2 years ago
7 0
Given that the density of gasoline is 0.77g/ml
This means that for every 1 ml of gasoline, the weight is 0.77g.

There are 1,000 ml in 1 litre, thus, there are 46 x 1,000 = 46,000 ml in 46 litres of gasoline.

Since there is 0.77g of gasoline in every ml. Thus in 46,000 ml there is 0.77 x 46,000 = 35,420 grams.

Given that a gram of gasoline produces 45.0kj of energy, then 35,420 gram will produce 45 x 35,420 = 1,593,900 kj.
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Jake's morning run was a distance of 9.3 miles. He ran back and forth on one long straight street. He started at his house and r
Sergeeva-Olga [200]

Answer: the distances can be 0.65 miles (in the opposite direction to the school) or 4.65 miles (in the same direction as the school)

Step-by-step explanation:

Ok, the data that we have is:

Total distance = 9.3 mi.

The travel is:

House to school = 4 mi.

school to library = A

library to house = B

Now, we have that:

4mi + A + B = 9.3mi.

We have three possibilities:

1) The order of locations is: house, library, school

The travel from: school to library + library to house is equivalent to a travel between the school to the house = 4mi.

Then we have A + B = 4mi

4mi + A + B = 8mi ≠ 9.3mi

Then the library can not be between the house and the school.

2) The order of locations is: house, school, library.

In this case we have that the distance between the library and the house is equal to the distance between the house and the school plus the distance between the school and the library, then:

4mi + A = B.

We can replace this in our original equation:

4mi + A + B = 9.3mi

4mi  + A + (4mi + A) = 9.3mi

8mi + 2*A = 9.3mi

2*A = 9.3mi - 8mi = 1.3mi

A = 1.3mi/2 = 0.65mi

Then the distance between the house and the library is:

The 4 miles between the house and the school, plus the 0.65 miles between the school and the library:

Distance = 4mi + 0.65mi. = 4,65mi

3) The third case is when the order of the locations is:

Library, house, school.

Then the distance between the house and the library is equal to the distance between the school and the library minus the distance between the house and the school, this is:

A - 4mi = B

Now we can replace this in our distance equation:

4mi + A + B = 9.3mi

4mi + A + (A - 4mi) = 9.3 mi

2A = 9.3mi

A = 9.3mi/2 = 4.65mi

Then the distance between the house and the library is:

B = A - 4mi = 4.65mi - A = 0.65mi

Then the distance between the house and the library is 0.65 miles in this case.

7 0
2 years ago
The equation 9(u – 2) + 1.5u = 8.25 models the total miles Michael traveled one afternoon while sledding, where u equals the num
MArishka [77]

Answer:

h = 2.5

Step by step explanation:

We have been given an equation 9(u-2)+1.5u=8.25 that models the total miles Michael traveled one afternoon while sledding, where u equals the number of hours walking up a hill and (u – 2) equals the number of hours sledding down the hill.

To find value of u we will solve our equation.

Upon using distributive property we will get,    

9(u-2)+1.5u=8.25

9u-18+1.5u=8.25

Now let us add 18 to both sides of our equation.

9u-18+18+1.5u=8.25+18

9u+1.5u=8.25+18

Now let us combine like terms.

10.5u=26.25

Upon dividing both sides of our equation by 10.5 we will get,

u=\frac{26.25}{10.5}

u=2.5

Therefore, value of u is 2.5.

7 0
2 years ago
Read 2 more answers
 A store is giving out cards labeled 1 through 10 when customers enter the store. If the card is an even​ number, you get a 15​%
liubo4ka [24]

Answer:

yes, this made alot of sence to me and i even thought wow what teacher wrote out this problem because it was so well done!

Step-by-step explanation:

hope this helped - Willow

8 0
2 years ago
What is the probability that a point chosen at random in the triangle is also in the blue square? A blue square inside of an uns
Dmitrij [34]

Answer:

One-third

Step-by-step explanation:

we know that

The probability that a point chosen at random in the triangle is also in the blue square is equal to divide the area of the square by the area of triangle

step 1

Determine the area of triangle

A=\frac{1}{2}(9)(6)=27\ in^2

step 2

Determine the area of the square

A=(3^2)=9\ in^2

step 3

Determine the probability

P=\frac{9}{27}

simplify

P=\frac{1}{3}

therefore

One-third

5 0
2 years ago
Hillel is juggling flaming torches to raise money for charity. His initial appearance raises \$500$500dollar sign, 500, and he r
Svetlanka [38]

Answer:

$R = $500 + $15(t)

Step-by-step explanation:

in this question, we are told to give a mathematical expression that would model the amount of money that is made by Hillel.

from the question, we were made to understand that the amount of money he makes is a front of his time t. that is noted.

and also, he has a base cost of $500.

now, let’s write an equation;

R = $500 + 15(t)

where t represents the length of the performance as suggested by women

3 0
2 years ago
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