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2 years ago

The diameter of the Moon is 3480 km. What is the surface area of the Moon?

2 answers:

8 0

You will need to convert the diameter to radius. 3840km diameter will be 1740km radius.

<span>4 x 3.1416 x 1740² = ~38,046,032km² surface area.</span>

Lelu [443]2 years ago

5 0

Answer:

Surface area of the moon is $S=3.8\times 10^{13}\ m^2$

Explanation:

It is given that,

Diameter of the moon, d = 3480 km

Radius of the moon, $r=1740\ km=1740\times 10^3\ m$

Moon is in the form of sphere. The surface area of the moon is given by :

$S=4\pi r^2$

$S=4\pi \times (1740\times 10^3)^2$

$S=3.8\times 10^{13}\ m^2$

So, the surface area of the moon is $3.8\times 10^{13}\ m^2$ . Hence, this is the required solution.

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Compressional stress on rock can cause strong and deep earthquakes, usually at _____.

valentinak56 [21]

The answer is reverse faults.

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2 years ago

A man pushes his child in a grocery cart. The total mass of the cart and child is 30.0 kg. If the force resisting the carts moti

-BARSIC- [3]

The force applied by the man is 60 N

Explanation:

We can solve this problem by applying Newton's second law, which states that:

$\sum F = ma$ (1)

where

$\sum F$ is the net force acting on the child+cart

m is the mass of the child+cart system

a is their acceleration

In this problem, we have:

m = 30.0 kg is the mass

$a=1.50 m/s^2$

And there are two forces acting on the child+cart system:

The forward force of pushing, F
The force resisting the cart motion, R = 15.0 N

Therefore we can write the net force as

$\sum F = F -R$

where R is negative since its direction is opposite to the motion

So eq.(1) can be rewritten as

$F-R=ma$

And solving for F,

$F=ma+R=(30.0)(1.50)+15.0=60 N$

Learn more about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

4 0

2 years ago

Fiber optic (FO) cables are based upon the concept of total internal reflection (TIR), which is achieved when the FO core and cl

kozerog [31]

Answer:

False

Explanation:

Though fiber active cable is based on the concept of internal reflection but it is achieved by refractive index which transmit data through fast traveling pulses of light. It has a layer of glass and insulating casing called “cladding,”and this is is wrapped around the central fiber thereby causing light to continuously bounce back from the walls of the Cable.

7 0

2 years ago

Now consider θc, the angle at which the blue refracted ray hits the bottom surface of the diamond. If θc is larger than the crit

Dennis_Churaev [7]

Complete Question:

A beam of white light is incident on the surface of a diamond at an angle $\theta_{a}$ , since the index of refraction depends on the light's wavelength, the different colors that comprise white light will spread out as they pass through the diamond. For example, the indices of refraction in diamond are $n_{red} = 2.410$ for red light and $n_{blue} = 2.450$ for blue light. Thus, blue light and red light are refracted at different angles inside the diamond. The surrounding air has $n_{air} = 1.000$ .

Now consider θc, the angle at which the blue refracted ray hits the bottom surface of the diamond. If θc is larger than the critical angle θcrit, the light will not be refracted out into the air, but instead it will be totally internally reflected back into the diamond. Find θcrit. Express your answer in degrees to four significant figures.

Answer:

$\theta_{crit} = 24.09^{0}$

Explanation:

Only the blue refracted ray is related to the critical angle in this question

$n_{air} = 1.000$

$n_{blue} = 2.450$

The relationship between the critical angle( $\theta_{crit}$ ), $n_{air}$ and $n_{blue}$ can be given as $sin \theta_{crit} = \frac{n_{air} }{n_{blue} }$

$sin \theta_{crit} = \frac{1 }{2.450 }\\\theta_{crit} = sin^{-1} \frac{1 }{2.450 }\\\theta_{crit} = sin^{-1} 0.4082^{0}\\ \theta_{crit} = 24.09^{0}$

6 0

2 years ago

Ferdinand the frog is hopping from lily pad to lily pad in search of a good fly

loris [4]

Answer: $36.86\°$

Explanation:

According to the described situation we have the following data:

Horizontal distance between lily pads: $d=2.4 m$

Ferdinand's initial velocity: $V_{o}=5 m/s$

Time it takes a jump: $t=0.6 s$

We need to find the angle $\theta$ at which Ferdinand jumps.

In order to do this, we first have to find the <u>horizontal component (or x-component)</u> of this initial velocity. Since we are dealing with parabolic movement, where velocity has x-component and y-component, and in this case we will choose the x-component to find the angle:

$V_{x}=\frac{d}{t}$ (1)